Jquery Ajax,从mvc.net控制器返回成功/错误

Eya*_*yal 55 asp.net-mvc jquery

我想控制何时回复错误消息和成功消息,但我总是收到错误消息:

这是我想要做的:

 $.ajax({
                type: "POST",
                data: formData,
                url: "/Forms/GetJobData",
                dataType: 'json',
                contentType: false,
                processData: false,

                success: function (response) {                    
                   alert("success!") 
                },
                error: function (response) {
                   alert("error") // I'm always get this.
                }

            });
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控制器:

         [HttpPost]
            public ActionResult GetJobData(Jobs jobData)
            {

              var mimeType = jobData.File.ContentType;
              var isFileSupported = AllowedMimeTypes(mimeType);

             if (!isFileSupported){        
                     //  Error
                    Response.StatusCode = (int)HttpStatusCode.BadRequest;
                    return Content("The attached file is not supported", MediaTypeNames.Text.Plain);    
             }
            else
              {
                    //  Success
                    Response.StatusCode = (int)HttpStatusCode.OK;
                    return Content("Message sent!", MediaTypeNames.Text.Plain);     

               }   

            }
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Eya*_*yal 116

 $.ajax({
    type: "POST",
    data: formData,
    url: "/Forms/GetJobData",
    dataType: 'json',
    contentType: false,
    processData: false,               
    success: function (response) {
        if (response.success) {
            alert(response.responseText);
        } else {
            // DoSomethingElse()
            alert(response.responseText);
        }                          
    },
    error: function (response) {
        alert("error!");  // 
    }

});
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控制器:

[HttpPost]
public ActionResult GetJobData(Jobs jobData)
{
    var mimeType = jobData.File.ContentType;
    var isFileSupported = IsFileSupported(mimeType);

    if (!isFileSupported){        
         //  Send "false"
        return Json(new { success = false, responseText = "The attached file is not supported." }, JsonRequestBehavior.AllowGet);
    }
    else
    {
        //  Send "Success"
        return Json(new { success = true, responseText= "Your message successfuly sent!"}, JsonRequestBehavior.AllowGet);
    }   
}
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- -补充: - -

基本上你可以用这种方式发送多个参数:

控制器:

 return Json(new { 
                success = true,
                Name = model.Name,
                Phone = model.Phone,
                Email = model.Email                                
            }, 
            JsonRequestBehavior.AllowGet);
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HTML:

<script> 
     $.ajax({
                type: "POST",
                url: '@Url.Action("GetData")',
                contentType: 'application/json; charset=utf-8',            
                success: function (response) {

                   if(response.success){ 
                      console.log(response.Name);
                      console.log(response.Phone);
                      console.log(response.Email);
                    }


                },
                error: function (response) {
                    alert("error!"); 
                }
            });
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  • `contentType:'application/json; charset = utf-8'`或`false`?为什么? (2认同)
  • 它总是会命中 ajax 调用的成功事件。我想要的是在某些内容不可用或错误时触发 ajax 调用的失败/错误处理程序。 (2认同)

SBi*_*are 30

使用Jsonclass而不是Content如下所示:

    //  When I want to return an error:
    if (!isFileSupported)
    {
        Response.StatusCode = (int) HttpStatusCode.BadRequest;
        return Json("The attached file is not supported", MediaTypeNames.Text.Plain);
    }
    else
    {
        //  When I want to return sucess:
        Response.StatusCode = (int)HttpStatusCode.OK; 
        return Json("Message sent!", MediaTypeNames.Text.Plain);
    }
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还设置contentType:

contentType: 'application/json; charset=utf-8',
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  • 我喜欢这个回答,提供了一个带有`Response.StatusCode`的示例. (4认同)

Tek*_*kin 13

当您从服务器返回值到 jQuery 的 Ajax 调用时,您还可以使用以下代码来指示服务器错误:

return StatusCode(500, "My error");
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或者

return StatusCode((int)HttpStatusCode.InternalServerError, "My error");
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或者

Response.StatusCode = (int)HttpStatusCode.InternalServerError;
return Json(new { responseText = "my error" });
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Http Success 代码以外的代码(例如 200[OK])将触发error:客户端(ajax)前面的函数。

你可以有 ajax 调用,如:

$.ajax({
        type: "POST",
        url: "/General/ContactRequestPartial",
        data: {
            HashId: id
        },
       success: function (response)  {
            console.log("Custom message : " + response.responseText);
        }, //Is Called when Status Code is 200[OK] or other Http success code
        error: function (jqXHR, textStatus, errorThrown)  {
            console.log("Custom error : " + jqXHR.responseText + " Status: " + textStatus + " Http error:" + errorThrown);
        }, //Is Called when Status Code is 500[InternalServerError] or other Http Error code
        })
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此外,您可以从 jQuery 端处理不同的 HTTP 错误,例如:

$.ajax({
        type: "POST",
        url: "/General/ContactRequestPartial",
        data: {
            HashId: id
        },
        statusCode: {
            500: function (jqXHR, textStatus, errorThrown)  {
                console.log("Custom error : " + jqXHR.responseText + " Status: " + textStatus + " Http error:" + errorThrown);
            501: function (jqXHR, textStatus, errorThrown)  {
                console.log("Custom error : " + jqXHR.responseText + " Status: " + textStatus + " Http error:" + errorThrown);
            }
        })
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statusCode: 当您想为从服务器返回的不同状态代码调用不同的函数时非常有用。

您可以在此处查看不同 Http 状态代码的列表:维基百科

其他资源:

  1. 从 AJAX 调用返回服务器端错误
  2. 在 JQuery Ajax 的 Error 函数中返回一个 JsonResult
  3. 使用 jQuery 处理 Ajax 错误