我有一个JSON对象流,看起来有点像这样:
{...}{...}{...}{...}...
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所以基本上是没有任何分隔符的JSON对象的连接列表.将这些反序列化为IEnumerable<T>使用JSON.NET 的正确方法是什么?此刻我尝试了类似的东西
var serializer = new JsonSerializer();
serializer.CheckAdditionalContent = false;
using (var reader = new StreamReader(stream))
using (var jsonReader = new JsonTextReader(reader)) {
reader.SupportMultipleContent = true;
reader.Read();
while (reader.TokenType != JsonToken.None) {
yield return serializer.Deserialize<TResult>(reader);
}
}
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但这失败了
Newtonsoft.Json.JsonSerializationException: Unexpected token while deserializing object: EndObject. Path '', line 1, position 55.
at Newtonsoft.Json.Serialization.JsonSerializerInternalReader.CreateValueInternal(JsonReader reader, Type objectType, JsonContract contract, JsonProperty member, JsonContainerContract containerContract, JsonProperty containerMember, Object existingValue)
at Newtonsoft.Json.Serialization.JsonSerializerInternalReader.Deserialize(JsonReader reader, Type objectType, Boolean checkAdditionalContent)
at Newtonsoft.Json.JsonSerializer.DeserializeInternal(JsonReader reader, Type objectType)
at Newtonsoft.Json.JsonSerializer.Deserialize[T](JsonReader reader)
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显然我需要在Deserialize通话结束后移动阅读器,但我该怎么办呢?
And*_*ker 16
我想如果你稍微改变你的循环一切应该工作:
public IEnumerable<TResult> ReadJson<TResult>(Stream stream)
{
var serializer = new JsonSerializer();
using (var reader = new StreamReader(stream))
using (var jsonReader = new JsonTextReader(reader))
{
jsonReader.SupportMultipleContent = true;
while (jsonReader.Read())
{
yield return serializer.Deserialize<TResult>(jsonReader);
}
}
}
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请注意,您必须遍历IEnumerable<TResult>,而Stream传递给此方法是开放的:
using (var stream = /* some stream */)
{
IEnumerable<MyClass> result = ReadJson<MyClass>(stream);
foreach (var item in result)
{
Console.WriteLine(item.MyProperty);
}
}
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示例: https ://dotnetfiddle.net/Y2FLuK