The*_* do 2 c++ internal-class
我一直认为内部类可以访问其外部类中的所有数据,但具有代码:
template<class T>
class Vector
{
template<class T>
friend
std::ostream& operator<<(std::ostream& out, const Vector<T>& obj);
private:
T** myData_;
std::size_t myIndex_;
std::size_t mySize_;
public:
Vector():myData_(nullptr),
myIndex_(0),
mySize_(0)
{ }
Vector(const Vector<T>& pattern);
void insert(const T&);
Vector<T> makeUnion(const Vector<T>&)const;
Vector<T> makeIntersection(const Vector<T>&)const;
class Iterator : public std::iterator<std::bidirectional_iterator_tag,T>
{
private:
T** itData_;
public:
Iterator()//<<<<<<<<<<<<<------------COMMENT
{ /*HERE I'M TRYING TO USE ANY MEMBER FROM Vector<T> AND I'M GETTING ERR SAYING:
ILLEGAL CALL OF NON-STATIC MEMBER FUNCTION*/}
Iterator(T** ty)
{
itData_ = ty;
}
Iterator operator++()
{
return ++itData_;
}
T operator*()
{
return *itData_[0];
}
bool operator==(const Iterator& obj)
{
return *itData_ == *obj.itData_;
}
bool operator!=(const Iterator& obj)
{
return *itData_ != *obj.itData_;
}
bool operator<(const Iterator& obj)
{
return *itData_ < *obj.itData_;
}
};
typedef Iterator iterator;
iterator begin()const
{
assert(mySize_ > 0);
return myData_;
}
iterator end()const
{
return myData_ + myIndex_;
}
};
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请参阅标记为COMMENT的行.
因此,在内部课程中,我或我不能使用外部成员吗?
不要打扰命名,它不是Vector它是一个Set.
谢谢.
您需要将外部类的实例传递给内部类.换句话说,您的Iterator类必须具有一个Vector方便实例的引用(或指针).执行此操作的最佳方法是让Iterator构造函数引用a Vector.
Iterator(Vector& v) : vec_(v)
{
vec_.do_something();
}
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