进一步过滤SQL结果

Question

我有一个使用SQL 2005返回正确结果集的查询.它如下:

select 
    case
    when convert(varchar(4),datepart(yyyy,bug.datecreated),101)+ ' Q' +convert(varchar(2),datepart(qq,bug.datecreated),101) = '1969 Q4' then '2009 Q2'
    else convert(varchar(4),datepart(yyyy,bug.datecreated),101)+ ' Q' +convert(varchar(2),datepart(qq,bug.datecreated),101)
    end as [Quarter],
    bugtypes.bugtypename,
    count(bug.bugid) as [Total]
from bug left outer join bugtypes on bug.crntbugtypeid = bugtypes.bugtypeid and bug.projectid = bugtypes.projectid
where 
    (bug.projectid = 44 
    and bug.currentowner in (-1000000031,-1000000045) 
    and bug.crntplatformid in (42,37,25,14))
or
    (bug.projectid = 44 
    and bug.currentowner in (select memberid from groupmembers where projectid = 44 and groupid in (87,88))
    and bug.crntplatformid in (42,37,25,14))

group by
    case
    when convert(varchar(4),datepart(yyyy,bug.datecreated),101)+ ' Q' +convert(varchar(2),datepart(qq,bug.datecreated),101) = '1969 Q4' then '2009 Q2' else convert(varchar(4),datepart(yyyy,bug.datecreated),101)+ ' Q' +convert(varchar(2),datepart(qq,bug.datecreated),101)
    end,
    bugtypes.bugtypename
order by 1,3 desc

它生成一个精美分组的年份和季度列表,一个关联的描述符,以及按降序计数顺序的事件计数.我想做的是进一步过滤这个,所以它只显示每季度提交的10个最常见的事件.

我正在努力的是如何采用这个结果集并实现这一目标.

Answer 1

您已按季度和总计订购.你尝试过使用过:

SELECT TOP 10

.....其余的查询

编辑: 阅读你的评论后,我意识到你需要使用RANK和Partition来完成这项工作.您可以在CTE中进行换行,如下所示:

;WITH IncidentsTable AS
(
   ... Insert Your Query here ...
)
SELECT * FROM
(
    SELECT [Quarter],
       BugTypeName,
       Total,
       Rank() OVER (Partition BY [Quarter] order by Total DESC) AS Ranking
     FROM
    IncidentsTable
)
WHERE
    Ranking <= 10
ORDER BY
      Quarter, Total;