lyo*_*eta 4 ruby csv arrays hash duplicates
我有一个哈希数组(实际上是CSV行),我需要查找并保留与两个特定键(用户,部分)匹配的所有行.以下是数据示例:
[
{ user: 1, role: "staff", section: 123 },
{ user: 2, role: "staff", section: 456 },
{ user: 3, role: "staff", section: 123 },
{ user: 1, role: "exec", section: 123 },
{ user: 2, role: "exec", section: 456 },
{ user: 3, role: "staff", section: 789 }
]
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所以我需要返回的是一个数组,其中只包含相同用户/节组合出现多次的行,如下所示:
[
{ user: 1, role: "staff", section: 123 },
{ user: 1, role: "exec", section: 123 },
{ user: 2, role: "staff", section: 456 },
{ user: 2, role: "exec", section: 456 }
]
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我正在尝试的双循环解决方案如下所示:
enrollments.each_with_index do |a, ai|
enrollments.each_with_index do |b, bi|
next if ai == bi
duplicates << b if a[2] == b[2] && a[6] == b[6]
end
end
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但由于CSV是145K行,因此它将永远消失.
如何才能更有效地获得我需要的输出?
在效率方面,您可能想尝试这样做:
grouped = csv_arr.group_by{|row| [row[:user],row[:section]]}
filtered = grouped.values.select { |a| a.size > 1 }.flatten
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第一个语句按:user
和:section
键对记录进行分组.结果是:
{[1, 123]=>[{:user=>1, :role=>"staff", :section=>123}, {:user=>1, :role=>"exec", :section=>123}],
[2, 456]=>[{:user=>2, :role=>"staff", :section=>456}, {:user=>2, :role=>"exec", :section=>456}],
[3, 123]=>[{:user=>3, :role=>"staff", :section=>123}],
[3, 789]=>[{:user=>3, :role=>"staff", :section=>789}]}
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第二个语句只选择具有多个成员的组的值,然后展平结果以便为您提供:
[{:user=>1, :role=>"staff", :section=>123},
{:user=>1, :role=>"exec", :section=>123},
{:user=>2, :role=>"staff", :section=>456},
{:user=>2, :role=>"exec", :section=>456}]
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这可以提高你的操作速度,但内存方面我不能说大输入会产生什么影响,因为它取决于你的机器,资源和文件的大小
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