使用逗号分隔符将double转换为2位小数

Question

在我看来,我有以下代码

IndexedContainer icLoaded = new IndexedContainer(); 
icLoaded.removeAllItems();  
icLoaded.removeAllContainerFilters();

icLoaded.addContainerProperty("Average Cost", Double.class, null);

在模型中我有以下代码

public IndexedContainer DoFetchstockCodesTable(String passedSQL,
        IndexedContainer passTable, String CustomsaleQuerry) {

    try {

        Class.forName(dbsettings.dbDriver);

        final Connection conn = DriverManager.getConnection(
                new Home().GiveMeSessionDB(), dbsettings.dbUsername,
                dbsettings.dbPassword);
        final Statement stmt = conn.createStatement();

        ResultSet rs = stmt.executeQuery(passedSQL.trim());

        while (rs.next()) {

            passTable.addItem(rs.getString("item_id"));

            passTable.getContainerProperty(rs.getString("item_id"),
                    "Average Cost").setValue(rs.getDouble("average_cost"));

我怎么能转换下面

 passTable.getContainerProperty(rs.getString("item_id"),
                    "Average Cost").setValue(rs.getDouble("average_cost"));

显示一个带有2个小数位的数字,用逗号分隔符分隔,如1,000.12使用

 NumberFormat numberFormat = new DecimalFormat("#,###.00");

当我使用下面的内容时,不显示任何内容.

 passTable.getContainerProperty(rs.getString("item_id"),
                    "Average Cost").setValue(numberFormat.format(rs.getDouble("average_cost")));

Answer 1

您调用NumberFormat#format(double)并保存格式double为a String,因为a double是原始值,并且没有固有的格式 -

NumberFormat numberFormat = new DecimalFormat("#,###.00");
double val = 1000.12;
System.out.println(numberFormat.format(val));

输出是

1,000.12

编辑

你需要改变它

icLoaded.addContainerProperty("Average Cost", Double.class, null);

至

icLoaded.addContainerProperty("Average Cost", String.class, null);