表达式树GetString结果

Question

我试图在从表达式创建查询时复制实体框架的行为,当我使用Attribute获取模型的属性时,我找到了使用ExpressionVisitor的方法

这是我到目前为止所得到的

    internal class NVisitor : ExpressionVisitor
    {
        private readonly ParameterExpression _parameter;
        private readonly Type _type;

        public NVisitor(Type type)
        {
            _type = type;
            _parameter = Expression.Parameter(type);
        }

        protected override Expression VisitParameter(ParameterExpression node)
        {
            return _parameter;
        }

        protected override Expression VisitMember(MemberExpression node)
        {

            if (node.Member.MemberType == MemberTypes.Property)
            {
                var memberName = node.Member.Name;

                PropertyInfo otherMember = _type.GetProperty(memberName);

                var ncols = node.Member.GetCustomAttributes(typeof(NColumn), true);

                if (ncols.Any())
                {
                    var ncol = (NColumn)ncols.First();

                    otherMember = _type.GetProperty(ncol.Name);
                }

                var inner = Visit(node.Expression);
                return Expression.Property(inner, otherMember);
            }

            return base.VisitMember(node);
        }
    }

我有一个属性NColumn,表示从表列的属性的真实名称,所以我按属性标记模型的属性

    public class BonusTypeX
    {
        [NColumn("BonusTypeName")]
        public string Name { get; set; }
    }

现在,当我试图得到表达,

    [TestMethod]
    public void ExpressionTesting2()
    {
        string searchKey = "Xmas";

        Expression<Func<BonusTypeX, bool>> expression = x => x.Name.Contains(searchKey);

        Type t = typeof(tbl_BonusType);

        var body = new NVisitor(t).Visit(expression.Body);

        string a = string.Join(".", body.ToString().Split('.').Skip(1));


        Assert.AreEqual("BonusTypeName.Contains(\"Xmas\")", a);
    }

我懂了

BonusTypeName.Contains(值(Payroll.Test.Administration.TestRepositories + <> c__DisplayClass13).searchKey)

我期待得到的是

BonusTypeName.Contains( "圣诞节")

是否有任何方法获取表达式字符串？我在用

string a = string.Join(".", body.ToString().Split('.').Skip(1));

我认为这可能是错误的.. :)

任何帮助,将不胜感激.

Answer 1

本地变量在运行时在编译器生成的类中捕获,这解释了该Payroll.Test.Administration.TestRepositories+<>c__DisplayClass13).searchKey部分.要在表达式中获取生成的字段值,必须在访问表达式时显式替换它的值:

protected override Expression VisitMember(MemberExpression node)
{    
    if (node.Member.MemberType == MemberTypes.Property)
    {
       var memberName = node.Member.Name;
       PropertyInfo otherMember = _type.GetProperty(memberName);
       var ncols = node.Member.GetCustomAttributes(typeof(NColumn), true);
       if (ncols.Any())
       {
          var ncol = (NColumn)ncols.First();
          otherMember = _type.GetProperty(ncol.Name);
       }

       var inner = Visit(node.Expression);
       return Expression.Property(inner, otherMember);
    }
    if (node.Member.MemberType == MemberTypes.Field)
    {
       if (node.Expression is ConstantExpression)
       {
          var owner = ((ConstantExpression)node.Expression).Value;
          var value = Expression.Constant(((FieldInfo)node.Member).GetValue(owner));
          return value;
       }
    }

    return base.VisitMember(node);
}