如何在图片框中旋转图像

Question

我正在制作一个winforms应用程序.我希望实现的功能之一是在家庭形式上的旋转装置.

装载主页时,应将鼠标悬停在齿轮图片上,并应将其旋转到位.

但到目前为止,我所拥有的只是RotateFlip而且只是翻转图片.

当鼠标悬停在齿轮上时,有没有办法让齿轮转动到位？

我到目前为止的代码是:

Bitmap bitmap1;
    public frmHome()
    {
        InitializeComponent();
        try
        {
            bitmap1 = (Bitmap)Bitmap.FromFile(@"gear.jpg");
            gear1.SizeMode = PictureBoxSizeMode.AutoSize;
            gear1.Image = bitmap1;
        }
        catch (System.IO.FileNotFoundException)
        {
            MessageBox.Show("There was an error." +
                "Check the path to the bitmap.");
        }
    }

    private void frmHome_Load(object sender, EventArgs e)
    {
        System.Threading.Thread.Sleep(5000);
    }

    private void frmHome_FormClosed(object sender, FormClosedEventArgs e)
    {
        Application.Exit();
    }

    private void pictureBox1_MouseHover(object sender, EventArgs e)
    {

        bitmap1.RotateFlip(RotateFlipType.Rotate180FlipY);
        gear1.Image = bitmap1;
    }

就像我说的,我只是想转动装备.我试图在Windows窗体应用程序中执行此操作.使用C#.框架4

Answer 1

你将不得不用来Timer创建旋转Image.没有用于旋转的内置方法.

创建全局计时器:

Timer rotationTimer;

在表单的构造函数中初始化计时器并创建PictureBox MouseEnter和MouseLeave事件:

//initializing timer
rotationTimer = new Timer();
rotationTimer.Interval = 150;    //you can change it to handle smoothness
rotationTimer.Tick += rotationTimer_Tick;

//create pictutrebox events
pictureBox1.MouseEnter += pictureBox1_MouseEnter;
pictureBox1.MouseLeave += pictureBox1_MouseLeave;

然后创建他们的Event Handlers:

void rotationTimer_Tick(object sender, EventArgs e)
{
    Image flipImage = pictureBox1.Image;
    flipImage.RotateFlip(RotateFlipType.Rotate90FlipXY);
    pictureBox1.Image = flipImage;
}

private void pictureBox1_MouseEnter(object sender, EventArgs e)
{
    rotationTimer.Start();
}

private void pictureBox1_MouseLeave(object sender, EventArgs e)
{
    rotationTimer.Stop();
}

Answer 2

你可以使用这样的Graphics.RotateTransform方法; 我使用双缓冲面板,一个Timer和两个类变量..

Bitmap bmp;
float angle = 0f;

private void Form1_Load(object sender, EventArgs e)
{
    bmp = new Bitmap(yourGrarImage);
    int dpi = 96;
    using (Graphics G = this.CreateGraphics()) dpi = (int)G.DpiX;
    bmp.SetResolution(dpi, dpi);
    panel1.ClientSize = bmp.Size;
}

private void timer1_Tick(object sender, EventArgs e)
{

    angle+=2;              // set the speed here..
    angle = angle % 360;
    panel2.Invalidate();
}


private void panel1_Paint(object sender, PaintEventArgs e)
{
    if (bmp!= null) 
    {
            float bw2 = bmp.Width / 2f;    // really ought..
            float bh2 = bmp.Height / 2f;   // to be equal!!!
            e.Graphics.TranslateTransform(bw2, bh2);
            e.Graphics.RotateTransform(angle);
            e.Graphics.TranslateTransform(-bw2, -bh2);
            e.Graphics.DrawImage(bmp, 0, 0);  
            e.Graphics.ResetTransform();
    }
}

private void panel1_MouseLeave(object sender, EventArgs e)
{
    timer1.Stop();
}

private void panel1_MouseHover(object sender, EventArgs e)
{
    timer1.Start();
    timer1.Interval = 10;    // ..and/or here
}

确保图像是方形的,中间有齿轮!! 这是一个很好的一个:

这是一个无闪烁的双缓冲面板:

public class Display : Panel
{
   public Display()
   {
      this.DoubleBuffered = true;
   }
}