PHP - 您可以为变量分配成员函数吗？

Question

在PHP5中,变量可以作为函数1进行评估,例如:

function myFunc() {
   echo "whatever";
}

$callableFunction = 'myFunc';

$callableFunction(); // executes myFunc()

是否有任何语法可以将对象成员函数分配给变量,例如:

class MyClass {
    function someCall() {
        echo "yay";
    }
}

$class = new MyClass();

// what I would like:
$assignedFunction = $class->someCall; // but I tried and it returns an error

$memberFunc = 'someCall';
$class->$memberFunc(); // I know this is valid, but I want a single variable to be able to be used to call different functions - I don't want to have to know whether it is part of a class or not.

// my current implementation because I don't know how to do it with anonymous functions:
$assignedFunction = function() { return $class->someCall(); } // <- seems lengthy; would be more efficient if I can just assign $class->someCall to the variable somehow?

$assignedFunction(); // I would like this to execute $class->someCall()

Answer 1

有一种方法,但对于PHP 5.4及以上...

class MyClass {
    function someCall() {
        echo "yay";
    }
}

$obj = new Myclass();

$ref = array($obj, 'someCall');

$ref();

嗯..实际上它也适用于静态,只需使用名称引用..

class MyClass {
    static function someCall2() {
        echo "yay2";
    }
}

$ref = array('MyClass', 'someCall2');

$ref();

对于非静态的,这种表示法也适用.它创建了一个类的临时实例.所以,这就是你需要的,只需要你需要php 5.4及以上版本)