无法读取JSON:无法识别的字段(...),未标记为可忽略

Mai*_*aik 3 rest spring json

是的,我知道这个问题已经讨论过几次了,但是我没有设法解决我的问题。

因此,我使用org.springframework.web.client.RestTemplate从http请求中获取了JSONObject

JSONObject j = RestTemplate.getForObject(url, JSONObject.class);
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但是我得到这个错误:

    Exception in thread "main" org.springframework.http.converter.HttpMessageNotReadableException: Could not read JSON: Unrecognized field "uri" (Class org.json.JSONObject), not marked as ignorable
 at [Source: sun.net.www.protocol.http.HttpURLConnection$HttpInputStream@6f526c5f; line: 2, column: 12] (through reference chain: org.json.JSONObject["uri"]); nested exception is org.codehaus.jackson.map.exc.UnrecognizedPropertyException: Unrecognized field "uri" (Class org.json.JSONObject), not marked as ignorable
 at [Source: sun.net.www.protocol.http.HttpURLConnection$HttpInputStream@6f526c5f; line: 2, column: 12] (through reference chain: org.json.JSONObject["uri"])
    at org.springframework.http.converter.json.MappingJacksonHttpMessageConverter.readJavaType(MappingJacksonHttpMessageConverter.java:181)
    at org.springframework.http.converter.json.MappingJacksonHttpMessageConverter.read(MappingJacksonHttpMessageConverter.java:173)
    at org.springframework.web.client.HttpMessageConverterExtractor.extractData(HttpMessageConverterExtractor.java:94)
    at org.springframework.web.client.RestTemplate.doExecute(RestTemplate.java:517)
    at org.springframework.web.client.RestTemplate.execute(RestTemplate.java:472)
    at org.springframework.web.client.RestTemplate.getForObject(RestTemplate.java:237)
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我想访问Rest-Api,并且Json对象可以具有不同的字段名称。我已经尝试过了@JsonIgnoreProperties(ignoreUnknown=true)。但这行不通...

如何将响应放入JSONObject?

ala*_*inm 5

您可以在Jackson 2.0中使用它:

ObjectMapper objectMapper = new ObjectMapper();
objectMapper.configure(
DeserializationFeature.FAIL_ON_UNKNOWN_PROPERTIES, false);
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如果您的版本是2.0之前的版本,请使用:

ObjectMapper objectMapper = new ObjectMapper();
objectMapper.configure(
DeserializationConfig.Feature.FAIL_ON_UNKNOWN_PROPERTIES, false);
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