使用XSLT删除xml标记

Question

我有以下xml文件:

<xfa:data>
  <form1>
    <Page1>
    <Page2>
    <contractInfo> ... </contractInfo>
    <paymentInfo> ... </paymentInfo>
  </form1>
  <commercialType> .... </commercialType>
  <userList> ... </userList>
  <officesList> ... </officesList>
  <commercialType> .... </commercialType>
  <userList> ... </userList>
  <officesList> ... </officesList>
  <commercialType> .... </commercialType>
  <userList> ... </userList>
  <officesList> ... </officesList>
</xfa:data>

我想删除commercialType,userList和officesList节点的每个发生,所以我的输出将是:

<xfa:data>
  <form1>
    <Page1>
    <Page2>
    <contractInfo> ... </contractInfo>
    <paymentInfo> ... </paymentInfo>
  </form1>
</xfa:data>

我怎么能用XSLT做到这一点？

谢谢

Answer 1

这种转变产生了预期的结果:

<xsl:stylesheet version="1.0"
 xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
 <xsl:output omit-xml-declaration="yes" indent="yes"/>

 <xsl:template match="node()|@*">
  <xsl:copy>
   <xsl:apply-templates select="node()|@*"/>
  </xsl:copy>
 </xsl:template>

 <xsl:template match="commercialType|userList|officesList"/>
</xsl:stylesheet>