为什么AngularJs的视图在异步Ajax调用后没有更新?

Meh*_*ran 3 jquery angularjs

为什么视图没有更新为"某人"?

var app = angular.module('Async', []);

app
  .controller('MainController', function($scope) {
    $scope.user = {
      name: "No one"
    };

    jQuery.ajax("/"
      , {
        async: true,
        type: "POST",
      }
    ).always(function() {
      $scope.user.name = "Someone";
      alert($scope.user.name);
    });
  });

angular.bootstrap(document, ['Async']);
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<div data-ng-controller="MainController">
  <div data-ng-view="">User's name: {{ user.name }}</div>
</div>

<script src="https://ajax.googleapis.com/ajax/libs/angularjs/1.2.23/angular.js"></script>
<script src="https://ajax.googleapis.com/ajax/libs/jquery/1.11.1/jquery.js"></script>
<script src="https://ajax.googleapis.com/ajax/libs/angularjs/1.2.23/angular-route.js"></script>
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Wad*_*ndy 5

当您在角度世界之外进行此类异步调用时,您需要通知角度您所做的任何更改.有几种方法可以解决此问题:

第一个选项:在你的回调中运行$ scope.$ apply()来告知angular你正在改变的事情:

jQuery.ajax("/"
  , {
    async: true,
    type: "POST",
  }
).always(function() {
  $scope.apply(function() {
    $scope.user.name = "Someone";
    alert($scope.user.name);
  })
});
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第二个选项(首选):jQuery.ajax使用angular的内置替换调用$http,这将为您处理$ apply步骤:

app
  .controller('MainController', function($scope, $http) {
    $scope.user = {
      name: "No one"
    };

    $http({
      method: 'POST',
      url: '/'
    }, function(successResponse) {
      $scope.user.name = successResponse.data.name;
      alert($scope.user.name);
    });
  });
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