sda*_*aau 25 makefile gnu-make
我已经看过如何从make目标手动调用另一个目标?,但我的问题有点不同; 考虑这个例子(注意,stackoverflow.com将选项卡更改为显示中的空格;但如果您尝试编辑,则选项卡将保留在源代码中):
TEXENGINE=pdflatex
pdflatex:
echo the engine is $(TEXENGINE)
lualatex:
TEXENGINE=lualatex
echo Here I want to call the pdflatex rule, to check $(TEXENGINE) there!
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在这里,如果我运行默认目标(pdflatex
),我得到预期的输出:
$ make pdflatex
echo the engine is pdflatex
the engine is pdflatex
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但是,有了目标lualatex
,我想:
make
变量更改TEXENGINE
为lualatex
,然后pdflatex
(使用它)相同的代码.我怎么能这样做?
很明显,在我的lualatex
规则中,我甚至没有设法更改TEXENGINE
变量,因为我在尝试时得到了这个:
$ make lualatex
TEXENGINE=lualatex
echo Here I want to call the pdflatex rule, to check pdflatex there!
Here I want to call the pdflatex rule, to check pdflatex there!
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...所以我真的想知道Makefiles中是否有这样的东西.
Jon*_*ely 33
目标特定变量还有一个特殊功能:当您定义特定于目标的变量时,变量值对此目标的所有先决条件及其所有先决条件等都有效(除非这些先决条件使用它们覆盖该变量)拥有特定于目标的变量值).
TEXENGINE=pdflatex
pdflatex:
echo the engine is $(TEXENGINE)
lualatex: TEXENGINE=lualatex
lualatex: pdflatex
echo Here I want to call the pdflatex rule, to check $(TEXENGINE) there!
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输出是:
$ make pdflatex
echo the engine is pdflatex
the engine is pdflatex
$ make lualatex
echo the engine is lualatex
the engine is lualatex
echo Here I want to call the pdflatex rule, to check lualatex there!
Here I want to call the pdflatex rule, to check lualatex there!
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好吧,我设法找到了一种解决方法,但我不太了解它-因此将不胜感激。对我来说,这些链接有帮助:
所以这是修改过的示例 - 显然,为了在之后从规则中调用规则(不是作为先决条件,而是作为后置条件),我只能递归调用make
,同时在其命令行上指定新变量值:
TEXENGINE=pdflatex
pdflatex:
echo the engine is $(TEXENGINE)
lualatex:
echo Here I want to call the pdflatex rule, to check $(TEXENGINE) there!
$(MAKE) TEXENGINE=lualatex pdflatex
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输出比我想要的更冗长,但它有效:
$ make lualatex
echo Here I want to call the pdflatex rule, to check pdflatex there!
Here I want to call the pdflatex rule, to check pdflatex there!
make TEXENGINE=lualatex pdflatex
make[1]: Entering directory `/tmp'
echo the engine is lualatex
the engine is lualatex
make[1]: Leaving directory `/tmp'
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...这就是我纯粹想要的命令行交互方式,但我知道这不是最好的解决方案(见下面@JonathanWakely 的评论)