gmu*_*mad 5 c++ qt qt4 qwidget
我有一个主要Widget和内部这个主要小部件我有QListWidget两个按钮.我已经覆盖了keyPressEvent主要小部件的内部(继承自QWidget).我可以keyPress在焦点未开启时收到事件QListWidget,但当焦点在QListWidget我内部时,我无法接收这些keyPress事件.以下是我用来实现此目的的代码:
MainWindow::MainWindow(QWidget *parent) :
QMainWindow(parent),
ui(new Ui::MainWindow)
{
ui->setupUi(this);
this->setFocusPolicy(Qt::StrongFocus);
ui->listWidget->addItem(new QListWidgetItem("Item1"));
ui->listWidget->addItem(new QListWidgetItem("Item2"));
ui->listWidget->addItem(new QListWidgetItem("Item3"));
}
MainWindow::~MainWindow()
{
delete ui;
}
void MainWindow::keyPressEvent(QKeyEvent *event)
{
qDebug() << "event->key(): " << event->key();
QWidget::keyPressEvent(event);
}
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Che*_*byl 11
在标题中:
protected:
bool eventFilter(QObject *obj, QEvent *event);
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在构造函数中:
qApp->installEventFilter(this);
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过滤:
bool MainWindow::eventFilter(QObject *obj, QEvent *event)
{
if (event->type() == QEvent::KeyPress)
{
QKeyEvent *keyEvent = static_cast<QKeyEvent *>(event);
qDebug() << "key " << keyEvent->key() << "from" << obj;
}
return QObject::eventFilter(obj, event);
}
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使用此事件过滤器,您可以捕获所有按键事件并检查谁发出事件(obj)
例如:
if ( obj == ui->listWidget )
//event from QListWidget
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根据你的评论:
bool MainWindow::eventFilter(QObject *obj, QEvent *event)
{
if (event->type() == QEvent::KeyPress)
{
if(obj == ui->listWidget)
{
QKeyEvent *keyEvent = static_cast<QKeyEvent *>(event);
if(keyEvent->key() == Qt::Key_Up)
qDebug() << "Up";
if(keyEvent->key() == Qt::Key_Down)
qDebug() << "Down";
}
}
return QObject::eventFilter(obj, event);
}
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