如何以pythonic方式做到这一点？

Question

考虑这个Python片段:

for a in range(10):

    if a == 7:
        pass
    if a == 8:
        pass
    if a == 9:
        pass
    else:
        print "yes"

如何写得更短？

#Like this or...
if a ?????[7,8,9]:
    pass

Answer 1

使用in运营商:

if a in (7,8,9):
    pass

Answer 2

要测试a是否属于某个范围:

if 7 <= a <= 9:
  pass

要测试a是否在给定的序列中:

if a in [3, 5, 42]:
  pass