多态控制器和调用对象

Question

我有一个多态关系,地址既可以由成员拥有,也可以由依赖者拥有.一切都看起来很棒,直到我意识到我不知道什么类型的物体正在创造它,除非我遗漏了什么.有没有办法告诉路由文件包含对象的类型？

楷模:

 class Member < ActiveRecord::Base
   has_one :address, as: :person, dependent: :destroy
 end

 class Dependent < ActiveRecord::Base
   has_one :address, as: :person, dependent: :destroy
 end

 class Address < ActiveRecord::Base
    belongs_to :person, polymorphic: true
 end

控制器:

 def new
  @person = ???
  @address = Address.new(person: @person)
 end

目前路线:

  resources :members do
    resources :addresses, shallow: true
    resources :dependents, shallow: true do
      resources :addresses, shallow: true
    end
  end

我有路由要在每个下面解决,但我需要检查params [:member_id]或params [:dependent_id].当我将笔记附加到一切时会发生什么.我可能在Rails中错过了一些简单的方法,任何建议都将非常感谢!

Answer 1

基本上你想在创建地址之前设置person对象.您可以在地址控制器中执行此操作,如下所示:

在地址控制器中:

class AddressesController < ApplicationController  
  before_action :set_person

  def new
    @address = @person.build_address
  end

  def set_person
    klass = [Member, Dependent].detect{|c| params["#{c.name.underscore}_id"]}
    @person= klass.find(params["#{klass.name.underscore}_id"])
  end
end

至于您的路线文件,目前根据您在模型中定义的关系,以下内容应该有效:

resources :members do
 resource :address #singular resource routing as its a has_one relationship
end

resources :dependents do
  resource :address #singular resource routing as its a has_one relationship
end

(请注意,我已经为嵌套资源使用了单数路由.您可以在这里阅读更多内容:http://guides.rubyonrails.org/routing.html#singular-resources)