Sou*_*der 56 android android-activity
到目前为止,我使用以下代码通过我的应用程序发送短信到另一部手机.
Intent intent = new Intent( Intent.ACTION_VIEW, Uri.parse( "sms:" + srcNumber));
intent.putExtra( "sms_body", message );
startActivity(intent);
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但是,这会打开本机消息传递应用程序,从而将我的应用程序活动置于后台.是否可以直接发送短信而无需打开本机消息应用程序?如果有,怎么样?
Him*_*wal 108
您可以通过以下方式从您的应用程序发送消息:
public void sendSMS(String phoneNo, String msg) {
try {
SmsManager smsManager = SmsManager.getDefault();
smsManager.sendTextMessage(phoneNo, null, msg, null, null);
Toast.makeText(getApplicationContext(), "Message Sent",
Toast.LENGTH_LONG).show();
} catch (Exception ex) {
Toast.makeText(getApplicationContext(),ex.getMessage().toString(),
Toast.LENGTH_LONG).show();
ex.printStackTrace();
}
}
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您还需要授予发送消息的SEND_SMS权限AndroidManifest.xml
<uses-permission android:name="android.permission.SEND_SMS" />
Abh*_*bey 14
public void sendLongSMS() {
String phoneNumber = "0123456789";
String message = "Hello World! Now we are going to demonstrate " +
"how to send a message with more than 160 characters from your Android application.";
SmsManager smsManager = SmsManager.getDefault();
ArrayList<String> parts = smsManager.divideMessage(message);
smsManager.sendMultipartTextMessage(phoneNumber, null, parts, null, null);
}
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并且不要忘记添加
<uses-permission android:name="android.permission.SEND_SMS"/>
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发送带有许可请求的短信:
附加清单:
<uses-permission android:name="android.permission.SEND_SMS" />
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添加Java函数:
void sendSmsMsgFnc(String mblNumVar, String smsMsgVar)
{
if (ActivityCompat.checkSelfPermission(this, Manifest.permission.SEND_SMS) == PackageManager.PERMISSION_GRANTED)
{
try
{
SmsManager smsMgrVar = SmsManager.getDefault();
smsMgrVar.sendTextMessage(mblNumVar, null, smsMsgVar, null, null);
Toast.makeText(getApplicationContext(), "Message Sent",
Toast.LENGTH_LONG).show();
}
catch (Exception ErrVar)
{
Toast.makeText(getApplicationContext(),ErrVar.getMessage().toString(),
Toast.LENGTH_LONG).show();
ErrVar.printStackTrace();
}
}
else
{
if (Build.VERSION.SDK_INT >= Build.VERSION_CODES.M)
{
requestPermissions(new String[]{Manifest.permission.SEND_SMS}, 10);
}
}
}
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是的,找到我自己问题的答案:)
相同地使用以下代码:
SmsManager sms = SmsManager.getDefault();
sms.sendTextMessage(srcNumber, null, message, null, null);
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这要求在Android清单xml上声明以下权限。
<uses-permission android:name="android.permission.SEND_SMS"/>
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发送带有交货报告的短信的完整功能。
//sent sms
private void sendSMS(String phoneNumber, String message) {
String SENT = "SMS_SENT";
String DELIVERED = "SMS_DELIVERED";
PendingIntent sentPI = PendingIntent.getBroadcast(this, 0, new Intent(SENT), 0);
PendingIntent deliveredPI = PendingIntent.getBroadcast(this, 0, new Intent(DELIVERED), 0);
// ---when the SMS has been sent---
registerReceiver(new BroadcastReceiver() {
@Override
public void onReceive(Context arg0, Intent arg1) {
switch (getResultCode()) {
case Activity.RESULT_OK:
Toast.makeText(getBaseContext(), "SMS sent",
Toast.LENGTH_SHORT).show();
break;
case SmsManager.RESULT_ERROR_GENERIC_FAILURE:
Toast.makeText(getBaseContext(), "Generic failure",
Toast.LENGTH_SHORT).show();
break;
case SmsManager.RESULT_ERROR_NO_SERVICE:
Toast.makeText(getBaseContext(), "No service",
Toast.LENGTH_SHORT).show();
break;
case SmsManager.RESULT_ERROR_NULL_PDU:
Toast.makeText(getBaseContext(), "Null PDU",
Toast.LENGTH_SHORT).show();
break;
case SmsManager.RESULT_ERROR_RADIO_OFF:
Toast.makeText(getBaseContext(), "Radio off",
Toast.LENGTH_SHORT).show();
break;
}
}
}, new IntentFilter(SENT));
// ---when the SMS has been delivered---
registerReceiver(new BroadcastReceiver() {
@Override
public void onReceive(Context arg0, Intent arg1) {
switch (getResultCode()) {
case Activity.RESULT_OK:
Toast.makeText(getBaseContext(), "SMS delivered",
Toast.LENGTH_SHORT).show();
break;
case Activity.RESULT_CANCELED:
Toast.makeText(getBaseContext(), "SMS not delivered",
Toast.LENGTH_SHORT).show();
break;
}
}
}, new IntentFilter(DELIVERED));
SmsManager sms = SmsManager.getDefault();
sms.sendTextMessage(phoneNumber, null, message, sentPI, deliveredPI);
}
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