是aov适合不平衡数据集.根据帮助...provides a wrapper to lm for fitting linear models to balanced or unbalanced experimental designs.但后来就说了aov is designed for balanced designs, and the results can be hard to interpret without balance.
我应该如何在R中的非平衡数据集上执行双向anova？
我想重现SAS输出的I型和III型平方和的不同结果(使用时proc glm).我记得我们type III sum of squares用于不平衡的数据集.
先感谢您.