如何按字母顺序在Python中连接多个排序文件?

ste*_*nix 3 python csv python-2.7

如何逐行读取多个CSV输入文件,比较每行中的字符,将第一行按字母顺序写入输出文件,然后前进最小值文件的指针,继续与所有文件进行比较,直到结束到达所有输入文件.这是一个针对解决方案的粗略计划.

buffer = []

for inFile in inFiles:

    f = open(inFile, "r")
    line = f.next()
    buffer.append([line, inFile])

#find minimum value in buffer alphabetically...
#write it to an output file...

#how do I advance one line in the file with the min value?
#and then continue the line-by-line comparisons in input files?
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fal*_*tru 5

你可以使用heapq.merge:

import heapq
import contextlib

files = [open(fn) for fn in inFiles]
with contextlib.nested(*files):
    with open('output', 'w') as f:
        f.writelines(heapq.merge(*files))
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在Python 3.x(3.3+)中:

import heapq
import contextlib

with contextlib.ExitStack() as stack:
    files = [stack.enter_context(open(fn)) for fn in inFiles]
    with open('output', 'w') as f:
        f.writelines(heapq.merge(*files))
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  • @stevetronix,如果你按照答案中的链接,你会看到:类似于sorted(itertools.chain(*iterables))**但返回一个iterable,不会一次将数据拉入内存**,并假设每个输入流已经排序(从最小到最大). (2认同)