即时通讯使用以下代码上传
protected void UploadButton_Click(object sender, EventArgs e)
{
if(FileUploadControl.HasFile)
{
try
{
string filename = Path.GetFileName(FileUploadControl.FileName);
FileUploadControl.SaveAs(Server.MapPath("~upload/") + filename);
StatusLabel.Text = "Upload status: File uploaded!";
}
catch(Exception ex)
{
StatusLabel.Text = "Upload status: The file could not be uploaded. The following error occured: " + ex.Message;
}
}
}
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我想更改上传文件名...我必须为每个上传的文件分配文件名如何?
该行获取上传文件的名称:
string filename = Path.GetFileName(FileUploadControl.FileName);
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该行告诉服务器将文件保存为:
FileUploadControl.SaveAs(Server.MapPath("~/") + filename);
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filename在保存之前,只需将值更改为其他值即可.
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