Fed*_*ssi 1 javascript php forms
我有一个表单,但它没有将参数'url'和'USERNAME'传递到下一页.有什么不对?
我必须使用<button>而不是<input>造型问题.
这是表格:
<form action="/confirmation/index.php" method="post" class="form-wrap">
<div class="loader-wrap">
<div class="loader-txt">
</div>
</div>
<div class="field-set url-field">
<input type="text" name="url" data-placeholder="Your Website URL" maxlength="50" class="validate">.
<button name="url_btn" type="button" class="btn url-btn">Scan My Site!</button>
</div>
<div class="field-set email-field">
<input type="text" name="USERNAME" data-placeholder="Your E-mail" maxlength="50" class="validate">
<button name="email_btn" type="button" class="btn email-btn" style="width:174px;font-size:15px;">Send me Results!</button>
</div>
</form>
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email_btn应该是type ="submit"而不是type ="button",所以相反:
<button type="submit">Send me the results</button>
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看这里:
http://www.w3schools.com/tags/tag_button.asp
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