将润滑功能改为星期一而不是星期日

Sam*_*ert 5 r lubridate

dates <- NULL

date <- as.Date("01/01/2014","%d/%m/%Y")

dates <- data.frame(date=as.Date(character())
                    ,cal_day_in_year_num = numeric()
                    ,cal_week_id = numeric()
                    ,cal_week_start_date = as.Date(character())
                    ,cal_week_end_date = as.Date(character())
)

for (i in 1:365) {

  dates[i,1] <- date + days(i-1) ## date

  dates[i,2] <- yday(dates[i,1]) ## cal_day_in_year_num

  dates[i,3] <- paste(year(dates[i,1]),sprintf("%02d",week(dates[i,1])),sep="") ## cal_week_id

  dates[i,4] <- floor_date(dates[i,1], "week") ## cal_week_start_date

  dates[i,5] <- ceiling_date(dates[i,1], "week") ## cal_week_end_date

}

View(dates)
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对于给定的日期,我正在尝试使用lubridate函数来计算一周的相应开始和结束日期

我遇到的问题是,每周的第一天是周日,我需要周一 - 有没有人有办法解决这个问题?

nog*_*pes 9

您可以使用自己的功能在base中执行此操作.例如,

start.of.week <- function(date)
  date - (setNames(c(6,0:5),0:6) [strftime(date,'%w')])

end.of.week <- function(date)
  date + (setNames(c(0,6:1),0:6) [strftime(date,'%w')])

start.of.week(as.Date(c('2014-01-05','2014-10-02','2014-09-22','2014-09-27')))
# "2013-12-30" "2014-09-29" "2014-09-22" "2014-09-22"
end.of.week(as.Date(c('2014-01-05','2014-10-02','2014-09-22','2014-09-27')))
# "2014-01-05" "2014-10-05" "2014-09-28" "2014-09-28"
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