有没有办法使用ON_CALL使模拟函数"有趣"？

Question

鉴于:

#include "gmock/gmock.h"
#include <string>

using namespace testing; // tsk, tsk

// -- -- -- -- -- -- -- -- -- -- -- -- -- -- -- -- -- -- -- -- --

struct Mockable {
    virtual std::string ify(int x) const;
};

std::string Mockable::ify(int x) const
{
    return std::to_string(x);
}

// -- -- -- -- -- -- -- -- -- -- -- -- -- -- -- -- -- -- -- -- --

struct Mocked : public Mockable {
    MOCK_CONST_METHOD1(ify, std::string(int));
};

// -- -- -- -- -- -- -- -- -- -- -- -- -- -- -- -- -- -- -- -- --

std::string tested(Mockable const& u, int x)
{
    return u.ify(x);
}

TEST(TC,T42)
{
    Mocked mock;
    ON_CALL(mock, ify(Eq(42)))
    .WillByDefault(Return("33"));

    std::string const& ret = tested(mock, 42);
    EXPECT_EQ("42", ret);
}

TEST(TC,T33)
{
    Mocked mock;
    ON_CALL(mock, ify(Eq(33)))
    .WillByDefault(Return("333"));

    std::string const& ret = tested(mock, 42);
    EXPECT_EQ("42", ret);
}

int main(int argc, char *argv[])
{
    ::testing::InitGoogleTest(&argc, argv);
    //::testing::FLAGS_gmock_verbose = "info";

    return RUN_ALL_TESTS();
}

输出是:

$ ./mocktest 
[==========] Running 2 tests from 1 test case.
[----------] Global test environment set-up.
[----------] 2 tests from TC
[ RUN      ] TC.T42

GMOCK WARNING:
Uninteresting mock function call - taking default action specified at:
mocktest.cc:40:
    Function call: ify(42)
          Returns: "33"
Stack trace:
mocktest.cc:44: Failure
Value of: ret
  Actual: "33"
Expected: "42"
[  FAILED  ] TC.T42 (0 ms)
[ RUN      ] TC.T33

GMOCK WARNING:
Uninteresting mock function call - returning default value.
    Function call: ify(42)
          Returns: ""
Stack trace:
mocktest.cc:54: Failure
Value of: ret
  Actual: ""
Expected: "42"
[  FAILED  ] TC.T33 (1 ms)
[----------] 2 tests from TC (1 ms total)

[----------] Global test environment tear-down
[==========] 2 tests from 1 test case ran. (1 ms total)
[  PASSED  ] 0 tests.
[  FAILED  ] 2 tests, listed below:
[  FAILED  ] TC.T42
[  FAILED  ] TC.T33

在这两种情况下,Gmock在应用行为时表现正确(或不在TC33中).但为什么在两种情况下都会说"无趣的模拟函数调用"呢？模拟函数调用仅在指定时才有意义EXPECT_CALL吗？

Answer 1

"只有在使用EXPECT_CALL指定时,模拟函数调用才有意义吗？"

简而言之,是的.
该ON_CALL()宏只影响将要采取的一个模拟的方法调用的动作,而不是调用预期的模拟对象上设置.

您可以使用NiceMock<>模板来抑制这些警告.
引用谷歌嘲笑"Cookbook"

假设您的测试使用模拟类MockFoo:

TEST(...) {
  MockFoo mock_foo;
  EXPECT_CALL(mock_foo, DoThis());
  ... code that uses mock_foo ...
}

如果调用除DoThis()之外的mock_foo方法,Google Mock会将其报告为警告.但是,如果您重写测试以改为使用NiceMock,则警告将消失,从而产生更清晰的测试输出:

using ::testing::NiceMock;

TEST(...) {
  NiceMock<MockFoo> mock_foo;
  EXPECT_CALL(mock_foo, DoThis());
  ... code that uses mock_foo ...
}

NiceMock<MockFoo>是它的子类MockFoo,因此它可以在任何MockFoo被接受的地方使用.