ActionResult to String

Question

我知道有很多类似的问题,但我没有得到任何我想要的答案.我希望通过执行类似的操作将ActionResult转换为String:

public ActionResult ProductDetail(int id)
{
    // ... lots of operations that include usage of ViewBag and a Model ...
    return View(product);
}

要向客户端显示产品页面,我希望能够通过JSON发送它,例如:

public JsonResult ProductDetailJSON(int id)
{
    // ... lots of operations that include usage of ViewBag and a Model ...
    return Json(new {
            html = this.ProductDetail(id).ToString(),
            name = ""
            // ... more properties
        }, JsonRequestBehavior.AllowGet);
}

因此,我将调用 Controller Action并获取其响应(a ActionResult,实际上是a ViewResult)并将其转换为a String,但是使用控制器方法的所有业务代码(包括,特别是ViewBag用法)创建它.

编辑澄清为什么我想这样做

我需要能够在浏览器中显示产品,因此我创建了一个名为的Controller Action ProductDetail,并且工作得很好.

在此之后需要一个API,为给定的产品提供一个带有一些元数据(如销售单位,名称等)和View的JSON对象.一种选择是发送一个链接到视图,这就是全部...但视图必须作为客户端要求内联.

为了避免代码重复并保持代码清洁,我想调用该方法ProductDetail,并捕获HTML Raw响应以将其作为一个内容放入JSON响应中String.

我见过其他人用这样的方法渲染View:

public string RenderRazorViewToString(string viewName, object model)
{
    ViewData.Model = model;
    using (var sw = new StringWriter())
    {
        var viewResult = ViewEngines.Engines.FindPartialView(ControllerContext, viewName);
        var viewContext = new ViewContext(ControllerContext, viewResult.View, ViewData, TempData, sw);
        viewResult.View.Render(viewContext, sw);
        viewResult.ViewEngine.ReleaseView(ControllerContext, viewResult.View);
        return sw.GetStringBuilder().ToString();
    }
}

但这种方式不会执行控制器逻辑.

Answer 1

这是一个有效的解决方案.

创建新类:

public class ResponseCapture : IDisposable
{
    private readonly HttpResponseBase response;
    private readonly TextWriter originalWriter;
    private StringWriter localWriter;
    public ResponseCapture(HttpResponseBase response)
    {
        this.response = response;
        originalWriter = response.Output;
        localWriter = new StringWriter();
        response.Output = localWriter;
    }
    public override string ToString()
    {
        localWriter.Flush();
        return localWriter.ToString();
    }
    public void Dispose()
    {
        if (localWriter != null)
        {
            localWriter.Dispose();
            localWriter = null;
            response.Output = originalWriter;
        }
    }
}

public static class ActionResultExtensions
{
    public static string Capture(this ActionResult result, ControllerContext controllerContext)
    {
        using (var it = new ResponseCapture(controllerContext.RequestContext.HttpContext.Response))
        {
            result.ExecuteResult(controllerContext);
            return it.ToString();
        }
    }
}

在你的json方法中这样做:

public JsonResult ProductDetailJSON(int id)
{
    // ... lots of operations that include usage of ViewBag and a Model ...
    return Json(new {
            // ControllerContext - modify it so it accepts Id
            html = View("ProductDetail").Capture(ControllerContext),
            name = ""
            // ... more properties
        }, JsonRequestBehavior.AllowGet);
}