我正在检查当前日期是否是工作日,如果不是,我想获得下一个工作日.工作日是周一至周五.
这是我尝试过的:
import time
from datetime import date,timedelta
dmy=time.strftime("%d-%m-%Y")# getting the current date
if dmy.strftime("%w") in set([6,7]): # checking if its a weekend( Sat/Sun) , if so advancing
dmy=time.strftime("%d-%m-%Y")+ timedelta(days=dmy.strftime("%w")%5) # this statement is not working, it errors out .
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声明dmy=time.strftime("%d-%m-%Y")+ timedelta(days=dmy.strftime("%w")%5))不起作用.什么是进入下一个工作日的最简单方法?
jon*_*rpe 10
你应该使用实际的date对象,而不是字符串:
>>> import datetime
>>> today = datetime.date.today()
>>> if today.isoweekday() in set((6, 7)):
today += datetime.timedelta(days=today.isoweekday() % 5)
>>> today
datetime.date(2014, 9, 30)
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请注意,isoweekday是1(星期一)至7(星期日),而weekday为0给6.
此外,请注意您的逻辑目前在星期六和星期日的两天增加了一天,这是不正确的 - 我想你想要:
>>> if today.isoweekday() in set((6, 7)):
today += datetime.timedelta(days=8 - today.isoweekday())
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例如:
>>> day = datetime.date(2014, 10, 4)
>>> day
datetime.date(2014, 10, 4) # Saturday
>>> if day.isoweekday() in set((6, 7)):
day += datetime.timedelta(days=8 - day.isoweekday())
>>> day
datetime.date(2014, 10, 6) # Monday
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