Bash Shell Scripting - 返回键/ Enter键

Question

我需要将我的输入与Enter/ Returnkey 进行比较......

read -n1 key
if [ $key == "\n" ]
   echo "@@@"
fi

但这不起作用..这段代码有什么问题

Answer 1

发布代码的几个问题.内联注释详细说明要修复的内容:

#!/bin/bash 
# ^^ Bash, not sh, must be used for read options

read -s -n 1 key  # -s: do not echo input character. -n 1: read only 1 character (separate with space)

# double brackets to test, single equals sign, empty string for just 'enter' in this case...
# if [[ ... ]] is followed by semicolon and 'then' keyword
if [[ $key = "" ]]; then 
    echo 'You pressed enter!'
else
    echo "You pressed '$key'"
fi

Answer 2

在进行比较之前定义空的 $IFS（内部字段分隔符）也是一个好主意，否则你最终会得到“”和“\n”相等。

所以代码应该是这样的：

# for distinguishing " ", "\t" from "\n"
IFS=

read -n 1 key
if [ "$key" = "" ]; then
   echo "This was really Enter, not space, tab or something else"
fi

Answer 3

如果有人想要使用包含倒计时循环的此类解决方案，我将添加以下代码仅供参考。

IFS=''
echo -e "Press [ENTER] to start Configuration..."
for (( i=10; i>0; i--)); do

printf "\rStarting in $i seconds..."
read -s -N 1 -t 1 key

if [ "$key" = $'\e' ]; then
        echo -e "\n [ESC] Pressed"
        break
elif [ "$key" == $'\x0a' ] ;then
        echo -e "\n [Enter] Pressed"
        break
fi

done