如何使用swift检查iphone型号

Question

我们如何在Swift中检查iPhone的型号(例如iPhone 4/iPhone5).使用以下代码我可以检查它是否是iPod的iPhone.

let iphoneModel = UIDevice.currentDevice().model
if (iphoneModel == "iPhone"){
        println("Iphone 4")
    }

我需要具体了解哪种iPhone型号.

Answer 1

使用以下代码.(参考)

enum UIUserInterfaceIdiom : Int
{
    case Unspecified
    case Phone
    case Pad
}

struct ScreenSize
{
    static let SCREEN_WIDTH         = UIScreen.mainScreen().bounds.size.width
    static let SCREEN_HEIGHT        = UIScreen.mainScreen().bounds.size.height
    static let SCREEN_MAX_LENGTH    = max(ScreenSize.SCREEN_WIDTH, ScreenSize.SCREEN_HEIGHT)
    static let SCREEN_MIN_LENGTH    = min(ScreenSize.SCREEN_WIDTH, ScreenSize.SCREEN_HEIGHT)
}

struct DeviceType
{
    static let IS_IPHONE_4_OR_LESS  = UIDevice.currentDevice().userInterfaceIdiom == .Phone && ScreenSize.SCREEN_MAX_LENGTH < 568.0
    static let IS_IPHONE_5          = UIDevice.currentDevice().userInterfaceIdiom == .Phone && ScreenSize.SCREEN_MAX_LENGTH == 568.0
    static let IS_IPHONE_6          = UIDevice.currentDevice().userInterfaceIdiom == .Phone && ScreenSize.SCREEN_MAX_LENGTH == 667.0
    static let IS_IPHONE_6P         = UIDevice.currentDevice().userInterfaceIdiom == .Phone && ScreenSize.SCREEN_MAX_LENGTH == 736.0
    static let IS_IPAD              = UIDevice.currentDevice().userInterfaceIdiom == .Pad && ScreenSize.SCREEN_MAX_LENGTH == 1024.0
}

并将其用作:

if DeviceType.IS_IPHONE_6P {
            println("IS_IPHONE_6P")
}

Answer 2

SWIFT 3

enum UIUserInterfaceIdiom : Int
{
    case Unspecified
    case Phone
    case Pad
}

struct ScreenSize
{
    static let SCREEN_WIDTH         = UIScreen.main.bounds.size.width
    static let SCREEN_HEIGHT        = UIScreen.main.bounds.size.height
    static let SCREEN_MAX_LENGTH    = max(ScreenSize.SCREEN_WIDTH, ScreenSize.SCREEN_HEIGHT)
    static let SCREEN_MIN_LENGTH    = min(ScreenSize.SCREEN_WIDTH, ScreenSize.SCREEN_HEIGHT)
}

struct DeviceType
{
    static let IS_IPHONE_4_OR_LESS  = UIDevice.current.userInterfaceIdiom == .phone && ScreenSize.SCREEN_MAX_LENGTH < 568.0
    static let IS_IPHONE_5          = UIDevice.current.userInterfaceIdiom == .phone && ScreenSize.SCREEN_MAX_LENGTH == 568.0
    static let IS_IPHONE_6          = UIDevice.current.userInterfaceIdiom == .phone && ScreenSize.SCREEN_MAX_LENGTH == 667.0
    static let IS_IPHONE_6P         = UIDevice.current.userInterfaceIdiom == .phone && ScreenSize.SCREEN_MAX_LENGTH == 736.0
    static let IS_IPAD              = UIDevice.current.userInterfaceIdiom == .pad && ScreenSize.SCREEN_MAX_LENGTH == 1024.0
}

并供使用

if DeviceType.IS_IPHONE_6P{
    print("IS_IPHONE_6P")
}

Answer 3

Swift 4 + iPhone Xr、Xs、Xs Max 支持

import UIKit

enum UIUserInterfaceIdiom : Int {
    case Unspecified
    case phone
    case pad
}

struct ScreenSize {
    static let screenWidth = UIScreen.main.bounds.size.width
    static let screenHeight = UIScreen.main.bounds.size.height
    static let screenMaxLength = max(ScreenSize.screenWidth, ScreenSize.screenHeight)
    static let screenMinLength = min(ScreenSize.screenWidth, ScreenSize.screenHeight)
}

struct DeviceType {
    static let iPhone4OrLess  = UIDevice.current.userInterfaceIdiom == .phone && ScreenSize.screenMaxLength < 568.0
    static let iPhoneSE = UIDevice.current.userInterfaceIdiom == .phone && ScreenSize.screenMaxLength == 568.0
    static let iPhone8 = UIDevice.current.userInterfaceIdiom == .phone && ScreenSize.screenMaxLength == 667.0
    static let iPhone8Plus = UIDevice.current.userInterfaceIdiom == .phone && ScreenSize.screenMaxLength == 736.0
    static let iPhoneXr = UIDevice.current.userInterfaceIdiom == .phone && ScreenSize.screenMaxLength == 896.0
    static let iPhoneXs = UIDevice.current.userInterfaceIdiom == .phone && ScreenSize.screenMaxLength == 812.0
    static let iPhoneXsMax = UIDevice.current.userInterfaceIdiom == .phone && ScreenSize.screenMaxLength == 896.0
    static let iPad = UIDevice.current.userInterfaceIdiom == .phone && ScreenSize.screenMaxLength == 1024.0
}

并使用：

 if DeviceType.iPhoneXsMax {
      print("is Max here")
 }