我试着写一些基本的聊天系统只是为了学习perl.我试图将聊天记录变成1个文件并打印新消息,如果它出现在chatlog.dat文件中,所以我写了一个功能几乎完全相同的东西,但我有一些问题,不知道如何解决它们.所以现在我有2个问题!
我无法理解如何保持checkFile功能始终处于活动状态(如多处理)以持续检查新消息
当我尝试编写将附加到聊天记录中的新消息时,会发生此问题.口译员在线上等待我的输入my $newMessage = <STDIN>;,但是,如果有人写了新消息怎么办?直到他按下进入才会显示...如何取消?
my ($sec,$min,$hour) = localtime();
while(1){
my $userMessage = <STDIN>;
last if $userMessage eq "::quit";
`echo "($hour:$min:$sec): $userMessage" >>chatlog.dat`;
}
sub checkFile{
my $lastMessage = "";
my $newMessage = "";
while (1) {
my $context = `cat chatlog.dat`;
split(/\n/, $context);
$newMessage = $_[$#_];
if ($newMessage ne $lastMessage) {
print $newMessage;
$lastMessage = $newMessage;
}
}
}
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sub checkFile{
my $lastMessage = "";
my $newMessage = "";
my $userName = $_[0];
while (1) {
my $context = `cat chatlog.dat`;
split(/\n/, $context);
$newMessage = $_[$#_];
if ($newMessage ne $lastMessage) {
$newMessage =~ /^\(.+\):\((.+)\) (.+$)/;
if ($1 ne $userName) { print "[$1]: $2";}
$lastMessage = $newMessage;
}
}
}
my $userName = "Rocker";
my ($sec,$min,$hour) = localtime();
my $thr = threads -> create ( \&checkFile, $userName ); #Starting a thread to continuously check for the file update
while (1) {
my $userMessage = <STDIN>; #STDIN will not interfere file checking
last if $userMessage eq "::quit";
`echo "($hour:$min:$sec):($userName) $userMessage" >>chatlog.dat` if $userMessage =~ /\S+/;
}
$thr -> join();
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