使用MultipartEntity帮助构建POST请求(新手问题)

Question

我想使用以下参数构造一个多部分请求:name(字符串),email(字符串)和fileupload(文件).我正在使用下面的Java代码(在Android中工作).

打印httppost.getRequestLine()

POST http://www.myurl.com/upload HTTP/1.1

所以在客户端站点上一切看起来都不错,但我的服务器(Django/Apache)将其作为GET请求读取,没有GET参数 - request.method生成'GET',request.GET.items()生成一个空字典.

我究竟做错了什么？我实际上并不知道如何正确设置多部分参数 - 使用猜测 - 所以这可能是问题所在.

public void SendMultipartFile() {
  Log.e(LOG_TAG, "SendMultipartFile");
  DefaultHttpClient httpclient = new DefaultHttpClient();
  HttpPost httppost = new HttpPost("http://www.myurl.com/upload");
  File file = new File(Environment.getExternalStorageDirectory(),
  "video.3gp");
  Log.e(LOG_TAG, "setting up multipart entity");
  MultipartEntity mpEntity = new MultipartEntity();
  ContentBody cbFile = new FileBody(file);
  mpEntity.addPart("fileupload", cbFile);
  Log.i("SendLargeFile", "file length = " + file.length());
  try {
   mpEntity.addPart("name", new StringBody(name));
   mpEntity.addPart("email", new StringBody(email));;
  } catch (UnsupportedEncodingException e1) {
   // TODO Auto-generated catch block
   Log.e(LOG_TAG, "UnsupportedEncodingException");
   e1.printStackTrace();
  }
  httppost.setEntity(mpEntity);
  Log.e(LOG_TAG, "executing request " + httppost.getRequestLine());
  HttpResponse response;
  try {
   Log.e(LOG_TAG, "about to execute");
   response = httpclient.execute(httppost);
   Log.e(LOG_TAG, "executed");
   HttpEntity resEntity = response.getEntity();
   Log.e(LOG_TAG, response.getStatusLine().toString());
   if (resEntity != null) {
    System.out.println(EntityUtils.toString(resEntity));
   }
   if (resEntity != null) {
    resEntity.consumeContent();
   }
  } catch (ClientProtocolException e) {
   // TODO Auto-generated catch block
   e.printStackTrace();
  } catch (IOException e) {
   // TODO Auto-generated catch block
   e.printStackTrace();
  }
 }

Answer 1

看来您可能找错地方了。您正在 POSTing，但在 request.GET 中查找数据：

尝试在“request.POST”和“request.FILES”中查找 QueryDict...

http://docs.djangoproject.com/en/1.6/ref/request-response/#django.http.HttpRequest.FILES