Adr*_* M. 10 php directory path
我有:
$page_file_temp = $_SERVER["PHP_SELF"];
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这将输出: /templates/somename/index.php
我只想从那条路径中提取 "/templates/somename/"
我该怎么做?谢谢!
Dav*_*vid 24
$page_directory = dirname($page_file_temp);
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见dirname.
也许这是你的解决方案:
$rootPath = $_SERVER['DOCUMENT_ROOT'];
$thisPath = dirname($_SERVER['PHP_SELF']);
$onlyPath = str_replace($rootPath, '', $thisPath);
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例如:
$_SERVER['DOCUMENT_ROOT'] 是这样的服务器的根路径 /home/abc/domains/abc.com/public_html
$_SERVER['PHP_SELF'] 是关于这样的脚本的完整路径 /home/abc/domains/abc.com/public_html/uploads/home/process.php
然后我们可以:
$rootPath 像这样 /home/abc/domains/abc.com/public_html
$thisPath 像这样 /home/abc/domains/abc.com/public_html/uploads/home
而$onlyPath像这样的/uploads/home