org.springframework.web.servlet.DispatcherServlet noHandlerFound

won*_*nza 5 java spring tomcat

访问http://api:8080/userswhich 404时出现此错误,并且在控制台中出现此错误:

2014 年 9 月 23 日下午 5:57:52 org.springframework.web.servlet.DispatcherServlet noHandlerFound 警告:在名称为“dispatcher”的 DispatcherServlet 中找不到带有 URI [/users] 的 HTTP 请求的映射

当我访问时http://localhost:8080/api/users,我的浏览器中出现 404,但我的控制台中没有错误

应用上下文.xml

<?xml version="1.0" encoding="UTF-8"?>
<beans xmlns="http://www.springframework.org/schema/beans"
    xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
    xmlns:p="http://www.springframework.org/schema/p"
    xmlns:context="http://www.springframework.org/schema/context"
    xsi:schemaLocation="
        http://www.springframework.org/schema/beans
        http://www.springframework.org/schema/beans/spring-beans.xsd
        http://www.springframework.org/schema/context
        http://www.springframework.org/schema/context/spring-context.xsd">

    <context:component-scan base-package="com.api"/>
</beans>
Run Code Online (Sandbox Code Playgroud)

调度程序servlet.xml:

<?xml version="1.0" encoding="UTF-8"?>
<beans xmlns="http://www.springframework.org/schema/beans"
  xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
  xmlns:p="http://www.springframework.org/schema/p"
  xmlns:aop="http://www.springframework.org/schema/aop"
  xmlns:tx="http://www.springframework.org/schema/tx"
  xmlns:context="http://www.springframework.org/schema/context"
  xmlns:mvc="http://www.springframework.org/schema/mvc"
  xsi:schemaLocation="http://www.springframework.org/schema/beans
    http://www.springframework.org/schema/beans/spring-beans-3.0.xsd
    http://www.springframework.org/schema/aop
    http://www.springframework.org/schema/aop/spring-aop-3.0.xsd
    http://www.springframework.org/schema/mvc
    http://www.springframework.org/schema/mvc/spring-mvc-3.0.xsd
            http://www.springframework.org/schema/context
            http://www.springframework.org/schema/context/spring-context.xsd
    ">

  <context:component-scan base-package="com.api"/>      
</beans>
Run Code Online (Sandbox Code Playgroud)

网页.xml:

<?xml version="1.0" encoding="UTF-8"?>
<web-app version="3.1" xmlns="http://xmlns.jcp.org/xml/ns/javaee" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xsi:schemaLocation="http://xmlns.jcp.org/xml/ns/javaee http://xmlns.jcp.org/xml/ns/javaee/web-app_3_1.xsd">

  <servlet>
    <servlet-name>dispatcher</servlet-name>
    <servlet-class>org.springframework.web.servlet.DispatcherServlet</servlet-class>
    <load-on-startup>2</load-on-startup>
  </servlet>
  <servlet-mapping>
    <servlet-name>dispatcher</servlet-name>
    <url-pattern>/</url-pattern>
  </servlet-mapping>
</web-app>
Run Code Online (Sandbox Code Playgroud)

用户.java:

package com.api;

import org.springframework.beans.factory.annotation.Autowired;
import org.springframework.stereotype.Controller;
import org.springframework.web.bind.annotation.RequestMapping;
import org.springframework.web.bind.annotation.RequestMethod;
import org.springframework.web.bind.annotation.RestController;

@RequestMapping("/users")
public class Users {
     @Autowired
     public Users() {

     }

    @RequestMapping(method = RequestMethod.GET)
    public void getUser() {
        System.out.println("\nhere\n");
    }
}
Run Code Online (Sandbox Code Playgroud)

如果有人有任何线索,我将不胜感激。我查了几个问题与我遇到的错误相同,但常见的解决方案是添加我已经有的问题,所以我不确定还能做什么。谢谢。

编辑:我刚刚将所有代码更新为最新的参考文档,但仍然出现相同的错误。编辑:更新以显示我当前的文件状态。

Jyo*_*yot 5

花了一整天后,我才知道解决方案。当您创建 maven 项目时,默认情况下它不会在“javaResource/src/main”下创建“java”文件夹,这是获取控制器路径所必需的。

确保首先在“javaResource/src/main”中创建 java 文件夹,然后创建包和控制器。

附上截图供参考。

在此处输入图片说明


Din*_* Tw 2

将您的 web.xml 更改为

<?xml version="1.0" encoding="UTF-8"?>
<web-app version="3.1" xmlns="http://xmlns.jcp.org/xml/ns/javaee" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xsi:schemaLocation="http://xmlns.jcp.org/xml/ns/javaee http://xmlns.jcp.org/xml/ns/javaee/web-app_3_1.xsd">

  <servlet>
    <servlet-name>dispatcher</servlet-name>
    <servlet-class>org.springframework.web.servlet.DispatcherServlet</servlet-class>
    <load-on-startup>2</load-on-startup>
  </servlet>
  <servlet-mapping>
    <servlet-name>dispatcher</servlet-name>
    <url-pattern>/</url-pattern>
  </servlet-mapping>
</web-app>
Run Code Online (Sandbox Code Playgroud)

和dispatch-servlet.xml到

<?xml version="1.0" encoding="UTF-8"?>
<beans xmlns="http://www.springframework.org/schema/beans"
  xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
  xmlns:p="http://www.springframework.org/schema/p"
  xmlns:aop="http://www.springframework.org/schema/aop"
  xmlns:tx="http://www.springframework.org/schema/tx"
  xmlns:context="http://www.springframework.org/schema/context"
  xmlns:mvc="http://www.springframework.org/schema/mvc"
  xsi:schemaLocation="http://www.springframework.org/schema/beans
    http://www.springframework.org/schema/beans/spring-beans-3.0.xsd
    http://www.springframework.org/schema/aop
    http://www.springframework.org/schema/aop/spring-aop-3.0.xsd
    http://www.springframework.org/schema/mvc
    http://www.springframework.org/schema/mvc/spring-mvc-3.0.xsd">

  <context:component-scan base-package="com.api"/>
</beans>
Run Code Online (Sandbox Code Playgroud)

您的代码不需要 applicationContext.xml 来运行