我正在编写一个自定义序列化程序,将双值转换为JSON对象中的字符串.我的代码到目前为止:
public String toJson(Object obj) throws IOException {
ObjectMapper mapper = new ObjectMapper();
SimpleModule module = new SimpleModule("DoubleSerializer", new Version(1, 0, 0, ""));
module.addSerializer(Double.class, new DoubleSerializer());
mapper.registerModule(module);
return mapper.writeValueAsString(obj);
}
public class DoubleSerializer extends JsonSerializer<Double> {
@Override
public void serialize(Double value, JsonGenerator jgen,
SerializerProvider provider) throws IOException,
JsonProcessingException {
String realString = new BigDecimal(value).toPlainString();
jgen.writeString(realString);
}
}
Run Code Online (Sandbox Code Playgroud)
这适用于Double(类成员),但不适用于double(基本类型)成员.例如,
public void test() throws IOException {
JsonMaker pr = new JsonMaker();
TestClass cl = new TestClass();
System.out.println(pr.toJson(cl));
}
class TestClass {
public Double x;
public double y;
public TestClass() {
x = y = 1111142143543543534645145325d;
}
}
Run Code Online (Sandbox Code Playgroud)
返回:{"x":"1111142143543543565865975808","y":1.1111421435435436E27}
有没有办法让它在两种情况下遵循相同的行为?
Sot*_*lis 12
您可以注册JsonSerializer原始类型double.
module.addSerializer(double.class, new DoubleSerializer());
Run Code Online (Sandbox Code Playgroud)