我正在尝试在我的 servlet 中构建一个 JSON 对象。该对象应如下所示:
{
"firms": [
{
"name": "firm1",
"projects": [
{
"name": "firm1project1"
},
{
"name": "firm1project2"
},
{
"name": "firm1project3"
}
]
},
{
"name": "firm2",
"projects": [
{
"name": "firm2project1"
},
{
"name": "firm2project2"
},
{
"name": "firm2project3"
}
]
},
{
"name": "firm3",
"projects": [
{
"name": "firm3project1"
},
{
"name": "firm3project2"
},
{
"name": "firm3project3"
}
]
},
{
"name": "firm4",
"projects": [
{
"name": "firm4project1"
},
{
"name": "firm4project2"
},
{
"name": "firm4project3"
}
]
}
]
}
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我在创建项目名称对象数组时遇到问题:
[
{
"name": "firm2project1"
},
{
"name": "firm2project2"
},
{
"name": "firm2project3"
}
]
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现在我有如下所示的代码(oJsonInner 是一个 JSONObject 对象,aProjects - JSONObject 类型的 ArrayList)。我根据从数据库查询获得的结果构建 oJsonInner 对象:
while(result.next()){
oJsonInner.put("name",result.getString("project_name"));
aProjects.add(oJsonInner);
}
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有什么方法可以获取 oJsonInner 对象的值,aProjects.add(oJsonInner);因此在下一个循环中我可以创建一个具有不同“project_name”值的新 oJsonInner 对象,而无需更新在第一个循环期间进入 aProjects 数组的对象?
while(result.next()){
oJsonInner = new JsonObject();
oJsonInner.put("name",result.getString("project_name"));
aProjects.add(oJsonInner);
}
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