Tak*_*aki 6 java google-app-engine
我用Java编写了一个Web API(泽西岛的JAX-RS),它使用JSON返回"403 Forbidden".
HTTP/1.1 403 Forbidden
Content-Type: application/json; charset=UTF-8
...
{"resultCode":"..."}
它按预期在本地GAE开发服务器上运行.但是,在真正的GAE上,内容类型从JSON更改为HTML.
HTTP/1.1. 403 Forbidden
Content-Type: text/html; charset=utf-8
...
<html><head>
<meta http-equiv="content-type" content="text/html;charset=utf-8">
<title>403 Forbidden</title>
</head>
<body text=#000000 bgcolor=#ffffff>
<h1>Error: Forbidden</h1>
</body></html>
如何防止GAE更改内容类型和实体主体？
我的端点不会抛出任何异常.它返回一个Response实例.下面的代码片段是测试端点.在本地GAE dev服务器上,此端点返回JSON.在真正的GAE上,它返回HTML.太好了.
import javax.ws.rs.GET;
import javax.ws.rs.Path;
import javax.ws.rs.core.MediaType;
import javax.ws.rs.core.Response;
import javax.ws.rs.core.Response.Status;
@Path("/test")
public class TestEndpoint
{
@GET
public Response get()
{
return Response
.status(Status.BAD_REQUEST)
.type(MediaType.APPLICATION_JSON_TYPE)
.entity("{\"id\":1}")
.build();
}
}
我写了一个更简单的示例代码,如下所示.即使在真正的GAE上,此代码也会返回JSON!有什么不同？
import java.io.IOException;
import java.io.PrintWriter;
import javax.servlet.ServletException;
import javax.servlet.http.HttpServlet;
import javax.servlet.http.HttpServletRequest;
import javax.servlet.http.HttpServletResponse;
public class TestServlet extends HttpServlet
{
@Override
protected void doGet(HttpServletRequest request, HttpServletResponse response)
throws ServletException, IOException
{
response.setStatus(400);
response.setContentType("application/json;charset=UTF-8");
PrintWriter out = response.getWriter();
out.write("{\"hello\":\"world\"}");
}
}
我阅读了泽西岛的源代码并直观地回答了这个问题.
将" jersey.config.server.response.setStatusOverSendError "(Jersey的服务器配置属性之一)设置为true可解决此问题.
以下是我的新web.xml的摘录.
<servlet>
<servlet-name>API</servlet-name>
<servlet-class>org.glassfish.jersey.servlet.ServletContainer</servlet-class>
<init-param>
<param-name>jersey.config.server.provider.classnames</param-name>
<param-value>
......
</param-value>
</init-param>
<init-param>
<param-name>jersey.config.server.response.setStatusOverSendError</param-name>
<param-value>true</param-value>
</init-param>
</servlet>
小智 0
您必须在服务上下文文件中定义自己的异常映射器和有效负载扩展：
<jaxrs:server id="my-resources" address="/some-context-path">
<jaxrs:serviceBeans>
<ref bean="my-resource-1" />
<ref bean="my-resource-2" />
</jaxrs:serviceBeans>
<jaxrs:extensionMappings>
<entry key="json" value="application/json"/>
<entry key="xml" value="application/xml"/>
</jaxrs:extensionMappings>
<jaxrs:providers>
<ref bean="jaxbProvider" />
<ref bean="my-custom-exception-mapper" />
</jaxrs:providers>
<jaxrs:features>
<cxf:logging/>
</jaxrs:features>
</jaxrs:server>
my-custom-exception-mapper 实现 ExceptionMapper、ResponseExceptionMapper。像这样的事情是一个好的开始： http://www.luckyryan.com/2013/06/15/apache-cxf-exception-handler-for-jaxrs-rest/
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