PHPUnit模拟异常

Question

我有一个处理错误的类,包括异常.如果捕获到异常,我会将异常作为参数传递给我的异常/错误处理程序.

try {
    someTrowingFnc();
} catch (\Exception $e) {
    this->error->exception($e);
}

现在我想对这个错误处理程序进行单元测试并模拟异常.

我发现很难模拟异常,以便我可以控制异常消息,文件和行.

$exceptionMock = $this->getMock('Exception', array(
    'getFile',
    'getLine',
    'getMessage',
    'getTrace'
)); // Tried all mock arguments like disable callOriginalConstructor

$exceptionMock->expects($this->any())
    ->method('getFile')
    ->willReturn('/file/name');

$exceptionMock->expects($this->any())
    ->method('getLine')
    ->willReturn('3069');

$exceptionMock->expects($this->any())
    ->method('getMessage')
    ->willReturn('Error test');

下面的代码结果总是返回NULL

$file   = $exception->getFile();
$line   = $exception->getLine();
$msg    = $exception->getMessage();

是否存在模拟异常的解决方法,或者我只是做错了什么？

Answer 1

返回错误详细信息(如getFile()etc)的Exception类方法被定义/声明为final方法.这是PHPUnit目前在模拟受保护,私有和最终方法的一个限制.

Limitations
Please note that final, private and static methods cannot be stubbed or mocked. They are ignored by PHPUnit's test double functionality and retain their original behavior.

如下所示:https://phpunit.de/manual/current/en/test-doubles.html