我只是无法解开else阻止.xCode给了我"修复它!和??"的选项,遗憾的是它也没有解决问题.我在xCode中遇到此错误:可选类型'String?'的值 没有打开; 你的意思是用!要么 ??
@IBAction func buttonTapped(theButton: UIButton) {
if answerField.text == "0" {
answerField.text = theButton.titleLabel?.text
} else {
answerField.text = answerField.text + theButton.titleLabel?.text
}
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ZYi*_*iOS 17
因为theButton.titleLabel?.text它没有被打开.
您可以使用
answerField.text = answerField.text + (theButton.titleLabel?.text ?? "")
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要么
if answerField.text == "0" {
answerField.text = theButton.titleLabel?.text
} else {
if let txt = theButton.titleLabel?.text {
answerField.text = answerField.text + txt
} else {
answerField.text = answerField.text
}
}
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