cURL - 将输出放入变量？

Question

我目前正在使用此C代码:

CURL *curl;
CURLcode res;

curl = curl_easy_init();
if (curl) {
    curl_easy_setopt(curl, CURLOPT_URL, "http://my-domain.org/");
    res = curl_easy_perform(curl);

    curl_easy_cleanup(curl);
}

它在控制台上打印输出.我怎样才能得到相同的输出,但是把它读成一个字符串？(这可能是一个基本问题,但我还不了解libcurl API ......)

谢谢你的帮助!

麦克风

Answer 1

您需要传递一个函数和缓冲区以将其写入缓冲区.

/* setting a callback function to return the data */
curl_easy_setopt(curl_handle, CURLOPT_WRITEFUNCTION, write_callback_func);

/* passing the pointer to the response as the callback parameter */
curl_easy_setopt(curl_handle, CURLOPT_WRITEDATA, &response);


/* the function to invoke as the data recieved */
size_t static write_callback_func(void *buffer,
                        size_t size,
                        size_t nmemb,
                        void *userp)
{
    char **response_ptr =  (char**)userp;

    /* assuming the response is a string */
    *response_ptr = strndup(buffer, (size_t)(size *nmemb));

}

请在这里查看更多信息.