lom*_*kat 11 iphone nscoding ios swift
我试图在我用swift编写的类上使用NSCoding协议,但似乎无法弄清楚为什么当我实现所需的方法时编译器抱怨它"不符合协议NSCoding":
class ServerInfo: NSObject, NSCoding {
var username = ""
var password = ""
var domain = ""
var location = ""
var serverFQDN = ""
var serverID = ""
override init() {
}
init(coder aDecoder: NSCoder!) {
self.username = aDecoder.decodeObjectForKey("username") as NSString
self.password = aDecoder.decodeObjectForKey("password") as NSString
self.domain = aDecoder.decodeObjectForKey("domain") as NSString
self.location = aDecoder.decodeObjectForKey("location") as NSString
self.serverFQDN = aDecoder.decodeObjectForKey("serverFQDN") as NSString
self.serverID = aDecoder.decodeObjectForKey("serverID") as NSString
}
func encodeWithCoder(_aCoder: NSCoder!) {
_aCoder.encodeObject(self.username, forKey: "username")
_aCoder.encodeObject(self.password, forKey: "password")
_aCoder.encodeObject(self.domain, forKey: "domain")
_aCoder.encodeObject(self.location, forKey: "location")
_aCoder.encodeObject(self.serverFQDN, forKey: "serverFQDN")
_aCoder.encodeObject(self.serverID, forKey: "serverID")
}
}
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这是一个错误还是我错过了一些东西?
Mar*_*n R 19
正如您在报告导航器中的详细编译器消息中所看到的,您的方法未正确声明:
error: type 'ServerInfo' does not conform to protocol 'NSCoding'
class ServerInfo: NSObject, NSCoding {
^
Foundation.NSCoding:2:32: note: protocol requires function 'encodeWithCoder' with type '(NSCoder) -> Void'
@objc(encodeWithCoder:) func encodeWithCoder(aCoder: NSCoder)
^
note: candidate has non-matching type '(NSCoder!) -> ()'
func encodeWithCoder(_aCoder: NSCoder!) {
^
Foundation.NSCoding:3:25: note: protocol requires initializer 'init(coder:)' with type '(coder: NSCoder)'
@objc(initWithCoder:) init(coder aDecoder: NSCoder)
^
note: candidate has non-matching type '(coder: NSCoder!)'
init(coder aDecoder: NSCoder!) {
(这可能在beta版本之间发生了变化.)此外,该initWithCoder方法必须标记为required:
required init(coder aDecoder: NSCoder) { }
func encodeWithCoder(_aCoder: NSCoder) { }
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在Swift 3中,所需的方法是
required init(coder aDecoder: NSCoder) { }
func encode(with aCoder: NSCoder) { }
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