我正在尝试通过Gmail PHP API发送电子邮件(https://developers.google.com/gmail/api/v1/reference/users/messages/send).一切似乎都达到了我发送信息的程度.我的代码是:
private function createMessage($email) {
$message = new Google_Service_Gmail_Message();
$message->setRaw(strtr(base64_encode($email), '+/=', '-_,')); // $email is a raw email data string
return $message;
}
public function sendMessage($userID, $email) {
try {
$msg = $this->createMessage($email);
$this->service->users_messages->send($userID, $msg);
} catch (Exception $e) {
print 'An error occurred: ' . $e->getMessage();
}
}
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代码在破线:
$this->service->users_messages->send($userID, $msg);
有错误:
An error occurred: Error calling POST https://www.googleapis.com/gmail/v1/users/myemailaddress@gmail.com/messages/send: (400) Invalid value for ByteString:
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知道这里发生了什么吗?谢谢!
像Eric所说的问题是url安全基础64.你需要将url转换更改为更像这样的东西:
$message_object = new Google_Service_Gmail_Message();
$encoded_message = rtrim(strtr(base64_encode("PUT MESSAGE HERE"), '+/', '-_'), '=');
$message_object->setRaw($encoded_message);
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还要确保使用有效的邮件mime,因此"PUT MESSAGE HERE"在现实中不起作用.你需要包含像主题等有效的标题.有一些不同的PHP库来制作这些,或者你可以用纯文本自己制作.