使用Ruby按值过滤JSON数组

loc*_*ost 8 ruby arrays json

我有一个看起来像这样的JSON数组.

[
 {"name":"Idaho","state":{"id":1,"name":"A"}},
 {"name":"Wyoming","state":{"id":1,"name":"A"}},
 {"name":"Montana","state":{"id":2,"name":"B"}},
 {"name":"South Dakota","state":{"id":1,"name":"B"}}
]
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我如何使用Ruby仅显示A的值?

我不认为sort_by会是答案,因为我在下面的内容只是按字母顺序对它们进行排序.我想完全排除B的所有结果.

.sort_by { |a| [a.state.name] }
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在.rb文件中执行此操作的最有效方法是什么?


我解决了自己的问题.这就是我实现我想要的方式.

.select { |a| a.state.name == "A" }
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Tod*_*obs 5

require 'json'

json = <<'JSON_STRING'
[
 {"name":"Idaho","state":{"id":1,"name":"A"}},
 {"name":"Wyoming","state":{"id":1,"name":"A"}},
 {"name":"Montana","state":{"id":2,"name":"B"}},
 {"name":"South Dakota","state":{"id":1,"name":"B"}}
]
JSON_STRING

data = JSON.parse json

data.map(&:values).select { |state, values| values["name"] == ?A }
#=> [["Idaho", {"id"=>1, "name"=>"A"}], ["Wyoming", {"id"=>1, "name"=>"A"}]]

data.map(&:values).select { |state, values| values["name"] == ?A }.map(&:first)
#=> ["Idaho", "Wyoming"]
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