创建Oracle序列触发器

use*_*388 7 oracle triggers sequence

我正在尝试创建seuqunce触发器,但是当我在SQL Developer中执行触发器创建sql时发生错误.我不明白,其实一切都很好.我在下面分享详细信息,请帮助我,谢谢.

我的触发器sql:

CREATE OR REPLACE TRIGGER "TRIGGER1" BEFORE INSERT ON ACCOUNTS
FOR EACH ROW
 WHEN (new."ID" IS NULL) 
BEGIN
  SELECT ACCOUNTS_SEQ.NEXTVAL 
  INTO :new."ID" 
  FROM dual;
END;
/
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和错误描述:

Error starting at line : 5 in command -
CREATE OR REPLACE TRIGGER "TRIGGER1" BEFORE INSERT ON ACCOUNTS
FOR EACH ROW
 WHEN (new."ID" IS NULL) 
BEGIN
  SELECT ACCOUNTS_SEQ.NEXTVAL 
  INTO :new."ID" 
  FROM dual
Error report -
SQL Command: tr?gger "TRIGGER1"
Failed: Warning: completed with warning

Error starting at line : 12 in command -
END
Error report -
Unknown Command
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Dar*_*ila 14

尝试以下方式:

CREATE OR REPLACE TRIGGER TRIGGER1
BEFORE INSERT ON ACCOUNTS
FOR EACH ROW
  WHEN (new.ID IS NULL)
BEGIN
  :new.ID := ACCOUNTS_SEQ.NEXTVAL;
END;
/
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你的序列应该是这样的

CREATE SEQUENCE ACCOUNTS_SEQ 
  START WITH 1 
  INCREMENT BY 1;
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希望能帮助到你.

  • 确保在块之后使用`/`. (2认同)