was*_*dev 38 javascript node.js express
我有一个如下所示的route.js:
module.exports = function(app) {
app.get('/tip', function(req, res) {
res.render("tip");
});
app.get('/article', function(req, res) {
res.render("article");
});
app.get('/article1', function(req, res) {
res.render("article1");
});
app.get('/article2', function(req, res) {
res.render("article2");
});
app.get('/article3', function(req, res) {
res.render("article3");
});
app.get('/modules/:name', function(req, res) {
var name = req.params.name;
res.render('modules/' + name);
});
app.get('/modules/esaver/:name', function(req, res) {
var name = req.params.name;
res.render('modules/esaver/' + name);
});
};
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考虑到我有超过200条不同的路线要创造,我最终会得到像'article1','article2'等东西
我的app.js就像:
var express = require('express')
,http = require('http')
,fs = require('fs')
,path = require('path');
var app = express();
html_templates = __dirname + '/html_templates';
app.set('views', html_templates + '/views');
app.set('view engine', 'jade');
app.use('/Core', express.static(__dirname + '/Core'));
app.listen(3000, function () {
console.log("express has started on port 3000");
});
require('./html_templates/controller/routes.js')(app);
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有没有动态的方法来创建它?
Alb*_*gni 49
我会做同样的事情 /modules/:name
app.get('/article/:id', function(req , res){
res.render('article' + req.params.id);
});
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从休息的角度来看,这将更有意义.
如果您因任何特殊原因无法执行此操作,您可能需要执行以下操作:
var articlesEndpoints = ['/article2', '/article3'];
articlesEndpoints.forEach(function(name) {
app.get(name, function(req, res) {
res.render(name);
});
});
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这是你的意思吗?
was*_*dev 15
终于搞定了..
在我得到的情况下,第1条,第2条等:
app.get('/:name(article|article2|article3)?', function(req, res) {
var name = req.params.name;
res.render(name);
});
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在我获得多级网址的情况下,我创建了一个自定义函数:
function geturl(url) {
app.get('/' + url + '/' + ':name', function(req, res){
var name = req.params.name;
res.render(url + '/' + name);
});
};
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以下是我创建动态 API 时所做的操作,同时我可以控制哪些 API 允许访问哪些方法。从现在开始要维护 API,您只需编辑 API 数组即可。
const APIs = [
{
route: 'order',
methods: ['get', 'post']
},
{
route: 'item',
methods: ['get']
},
]
APIs.forEach(api => {
api.methods.forEach(method => {
app[method]('/' + api.route, (req, res) => require('./routes/' + api.route)[method](req, res))
})
})
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有很多方法可以实现动态快速路由.它在很大程度上取决于你在项目中实现的结构,这里我留下一个动态路由的例子,我希望它会有用.
RouterService.js
module.exports = (function(myCustomRoutes) {
let express = require('express');
let router = express.Router();
let methods = Object.keys(myCustomRoutes); // getting methods ('get', 'post'... etc)
let routesMethod = null;
let url = null;
for(i in methods) {
routesMethod = Object.keys(myCustomRoutes[methods[i]]);
for(j in routesMethod) {
url = '/' + routesMethod[j];
url += '/:' + myCustomRoutes[methods[i]][routesMethod[j]].params.join('/:');console.log(url);
router[methods[i]](url, myCustomRoutes[methods[i]][routesMethod[j]].controller);
}
}
return router;
})();
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CustomRoutes.js
module.exports = (function() {
let routes = {get: {}, post: {}};
let routerService = require('./RouterService');
// GET: /dynamic1
routes.get.dynamic1 = {
params: [],
controller: function(req, res, next) {
res.send('route 1');
}
};
// GET: /dynamic2/:param1
routes.get.dynamic2 = {
params: [':param1'],
controller: function(req, res, next) {
res.send('route 2');
}
};
// POST: /dynamic3/:param1/:param1
routes.post.dynamic3 = {
params: ['param1', 'param2'],
controller: function(req, res, next) {
res.send('route 3');
}
};
/*
* Export a router with paths
* GET: /dynamic1
* GET: /dynamic2/:param1
* POST: /dynamic3/:param1/:param1
**/
return routerService(routes);
})();
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app.js
let express = require('express');
let app = express();
/*
* Option 1
* GET: /dynamic1
* GET: /dynamic2/:param1
* POST: /dynamic3/:param1/:param1
**/
app.use(require('CustomRoutes')());
/*
* Option 2
* GET: /api/v1/dynamic1
* GET: /api/v1/dynamic2/:param1
* POST: /api/v1/dynamic3/:param1/:param1
**/
app.use('/api/v1', require('CustomRoutes')());
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