$MyInspiration.MyCommand.Name 提供奇怪的结果

Question

为什么$MyInvocation.MyCommand.Name在函数内执行时会给出函数的名称？据此，它旨在为您提供脚本文件名。这是我正在使用的代码：

function startScript
{
    $ScriptName = $MyInvocation.MyCommand.Name
    $ScriptName
}

$ScriptName = $MyInvocation.MyCommand.Name
$ScriptName

startScript

<#
Output:

testing.ps1
startScript
#>

Answer 1

根据PowerShell 文档：

$MyInvocation
       Contains an information about the current command, such as the name, 
       parameters, parameter values, and information about how the command was
       started, called, or "invoked," such as the name of the script that called
       the current command. 

       $MyInvocation is populated only for scripts, function, and script blocks. 
       You can use the information in the System.Management.Automation.InvocationInfo
       object that $MyInvocation returns in the current script, such as the path
       and file name of the script ($MyInvocation.MyCommand.Path) or the name of a
       function ($MyInvocation.MyCommand.Name) to identify the current command. 
       This is particularly useful for finding the name of the current script.

如果您对脚本路径感兴趣，另请参阅以下段落：

   Beginning in Windows PowerShell 3.0, $MyInvocation has the following new
   properties. 

   -- PSScriptRoot: Contains the full path to the script that invoked the
      current command. The value of this property is populated only when
      the caller is a script.