我有以下代码:
UIWebView.loadRequest(NSURLRequest(URL: NSURL(string: "google.ca")))
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我收到以下错误:
'NSURLRequest'无法转换为UIWebView.
知道问题是什么吗?
Mic*_*lum 58
loadRequest:是一个实例方法,而不是类方法.您应该尝试使用UIWebview实例作为接收器而不是类本身来调用此方法.
webviewInstance.loadRequest(NSURLRequest(URL: NSURL(string: "google.ca")!))
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但是,正如@radex在下面正确指出的那样,你也可以利用currying来调用这个函数:
UIWebView.loadRequest(webviewInstance)(NSURLRequest(URL: NSURL(string: "google.ca")!))
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har*_*bar 32
Swift中的UIWebView
@IBOutlet weak var webView: UIWebView!
override func viewDidLoad() {
super.viewDidLoad()
let url = URL (string: "url here")
let requestObj = URLRequest(url: url!)
webView.loadRequest(requestObj)
// Do any additional setup after loading the view.
}
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Nag*_*jun 27
试试这个:
将UIWebView添加到View.
使用助理编辑器连接UIWebview插座并命名您的"webview".
UIWebView加载URL.
@IBOutlet weak var webView: UIWebView!
override func viewDidLoad() {
super.viewDidLoad()
// Your webView code goes here
let url = URL(string: "https://www.example.com")
let requestObj = URLRequest(url: url! as URL)
webView.load(requestObj)
}
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xsc*_*der 10
Swift 3在URL和URLRequest上不再使用NS前缀,因此更新的代码将是:
let url = URL(string: "your_url_here")
yourWebView.loadRequest(URLRequest(url: url!))
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在Swift 3中你可以这样做:
@IBOutlet weak var webview: UIWebView!
override func viewDidLoad() {
super.viewDidLoad()
// Web view load
let url = URL (string: "http://www.example.com/")
let request = URLRequest(url: url!)
webview.loadRequest(request)
}
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请记住添加权限Info.plist
,添加以下值:
在 Swift 4 或 4.2 你可以使用像:
你的观点如下:
import UIKit
import WebKit
class ViewController: UIViewController {
@IBOutlet weak var wkwebview: WKWebView!
override func viewDidLoad() {
super.viewDidLoad()
let request = URLRequest(url: URL(string: "**your URL**")!)
wkwebview?.load(request)
}
}
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<key>NSAppTransportSecurity</key>
<dict>
<key>Allow Arbitrary Loads</key>
<true/>
</dict>
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注意 info.plist 将如下所示
Swift 3 - Xcode 8.1
@IBOutlet weak var myWebView: UIWebView!
override func viewDidLoad() {
super.viewDidLoad()
let url = URL (string: "https://ir.linkedin.com/in/razipour1993")
let requestObj = URLRequest(url: url!)
myWebView.loadRequest(requestObj)
}
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斯威夫特3
@IBOutlet weak var webview: UIWebView!
webview.loadRequest(URLRequest(url: URL(string: "https://www.yourvideo.com")!))
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简单、经过测试且 100% 有效
导入网络工具包:
import WebKit
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将 IBOutlet 分配给 webview:
var webView : WKWebView!
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设置委托:
class ViewController: UIViewController , WKNavigationDelegate{
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在viewDidLoad()上编写代码:
// loading URL :
let myBlog = "/sf/users/322009551/?tab=profile"
let url = NSURL(string: myBlog)
let request = NSURLRequest(url: url! as URL)
// init and load request in webview.
webView = WKWebView(frame: self.view.frame)
webView.navigationDelegate = self
webView.load(request as URLRequest)
self.view.addSubview(webView)
self.view.sendSubview(toBack: webView)
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编写委托方法:
//MARK:- WKNavigationDelegate
func webView(webView: WKWebView, didFailProvisionalNavigation navigation: WKNavigation!, withError error: NSError) {
print(error.localizedDescription)
}
func webView(webView: WKWebView, didStartProvisionalNavigation navigation: WKNavigation!) {
print("Strat to load")
}
func webView(webView: WKWebView, didFinishNavigation navigation: WKNavigation!) {
print("finish to load")
}
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在迅速5
import UIKit
import WebKit
class ViewController: UIViewController, WKUIDelegate {
var webView: WKWebView!
override func viewDidLoad() {
super.viewDidLoad()
let myURL = URL(string:"https://www.apple.com")
let myRequest = URLRequest(url: myURL!)
webView.load(myRequest)
}
override func loadView() {
let webConfiguration = WKWebViewConfiguration()
webView = WKWebView(frame: .zero, configuration: webConfiguration)
webView.uiDelegate = self
view = webView
}
}
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