Parsley JS将错误/成功类添加到父级

cus*_*ice 4 javascript jquery parsley.js

我正在使用Parsley JS(http://parsleyjs.org/)进行表单验证.错误的默认行为是parsley-error为每个无效输入添加一个类.但是,我想更改默认行为并将错误类添加到输入的父级 - 特别是在form-group元素上.

基本的HTML

<form class="js-contact-form">

  <!-- this field is just required, it would be validated on form submit -->
  <div class="form-group">
    <label for="fullname">Full Name * :</label>
    <input type="text" class="form-control" name="fullname" placeholder="Name" required />
  </div>

  <!-- this required field must be an email, and validation will be run on field change -->
  <div class="form-group">
    <label for="email">Email * :</label>
    <input type="email" class="form-control" name="email" data-parsley-trigger="change" />
  </div>

  <input type="submit" />
</form>
Run Code Online (Sandbox Code Playgroud)

我正在使用"Javascript安装"来初始化所有内容,我尝试用我自己的函数覆盖"errorClass"和"successClass"选项,但似乎不起作用.

 $('.js-contact-form').parsley({
    trigger:      'change',
    errorClass:   function(){
      $(this).parent()
           .removeClass('has-success')
           .addClass('has-error has-feedback');
    },
    successClass: function(){
      $(this).parent()
           .removeClass('has-error')
           .addClass('has-success has-feedback');
    },
    errorsWrapper: '<div class="invalid-message"></div>',
    errorTemplate: '<span></span>',
});
Run Code Online (Sandbox Code Playgroud)

我想最终得到这样的东西:

<div class="form-group has-feedback has-error">
  <label for="fullname">Full Name * :</label>
  <input type="text" class="form-control" name="fullname" placeholder="Name" required />
  <div class="invalid-message">
     <span>This field is required</span>
  </div>
</div>
Run Code Online (Sandbox Code Playgroud)

Luí*_*ruz 18

你应该使用classHandler而不是errorClass.

这应该工作:

$(document).ready(function() {
    $('.js-contact-form').parsley({
        trigger:      'change',
        successClass: "has-success",
        errorClass: "has-error",
        classHandler: function (el) {
            return el.$element.closest('.form-group'); //working
        },
        errorsWrapper: '<div class="invalid-message"></div>',
        errorTemplate: '<span></span>',
    });
});
Run Code Online (Sandbox Code Playgroud)

你也可以在SO上查看这个相关的答案:parsley 2.0.3不能使用boostrap 3