cjk*_*cjk 98
用这个:
SELECT * FROM Table WHERE Column LIKE '%[0-9]%'
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DECLARE @str AS VARCHAR(50)
SET @str = 'PONIES!!...pon1es!!...p0n1es!!'
IF PATINDEX('%[0-9]%', @str) > 0
PRINT 'YES, The string has numbers'
ELSE
PRINT 'NO, The string does not have numbers'
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