如何从自定义QMessageBox捕获按钮单击？

Question

如何修改下面的自定义QMessageBox的代码,以便知道用户是单击"是"还是"否"？

from PySide import QtGui, QtCore

# Create a somewhat regular QMessageBox
msgBox = QtGui.QMessageBox( QtGui.QMessageBox.Question, "My title", "My text.", QtGui.QMessageBox.Yes | QtGui.QMessageBox.No )

# Get the layout
question_layout = msgBox.layout()

# Additional widgets to add to the QMessageBox
qlabel_workspace_project = QtGui.QLabel('Some random data window:')
qtextedit_workspace_project = QtGui.QTextEdit()
qtextedit_workspace_project.setReadOnly(True)

# Add the new widgets
question_layout.addWidget(qlabel_workspace_project,question_layout.rowCount(), 0, 1, question_layout.columnCount() )
question_layout.addWidget(qtextedit_workspace_project,question_layout.rowCount(), 0, 1, question_layout.columnCount() )

# Show widget
msgBox.show()

Answer 1

而不是show你应该使用该exec_方法,所有继承自的小部件QDialog都具有:

http://doc.qt.io/qt-4.8/qmessagebox.html#exec

此方法将阻塞,直到msgbox关闭并返回结果:

result = msgBox.exec_()
if result == QtGui.QMessageBox.Yes:
    # do yes-action
else:
    # do no-action