sla*_*fer 3 amazon-web-services amazon-redshift
有很多谷歌结果可以回答这个问题。然而,似乎没有一个对我有用。因此,我正在创建这个问题并回答它以供我自己将来参考以及可能通过 Google 访问此线程的任何其他人。
这是查询:
select sum(mbytes)/1024, database from (
select trim(pgdb.datname) as Database,
trim(a.name) as Table, b.mbytes
from stv_tbl_perm a
join pg_database as pgdb on pgdb.oid = a.db_id
join (select tbl, count(*) as mbytes
from stv_blocklist group by tbl) b on a.id=b.tbl
where a.slice=0
order by db_id, name)
group by database;
输出:
?column? |   database
----------+---------------
       62 | db1
       33 | db2
       33 | db3
        2 | db4
       37 | db5
       34 | db6
       35 | db7
       59 | db8
        2 | db9
       26 | db10
        2 | db11
       72 | db12
       36 | db13
       41 | db14
注:以上数字以 GB 为单位
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