如何将原始相机数据转换为Android上的位图

Question

我从库函数中获取rawData了类型的原始相机数据byte[],格式为RGBA,大小为640x480,每像素4个字节.我需要将其转换为位图并在屏幕上的ImageView中显示.

我所做的是以下内容:

byte[] JPEGData = convertToJpeg(rawData, 640, 480, 80);
Bitmap bitmap = BitmapFactory.decodeByteArray(JPEGData , 0, JPEGData .length);    
imageView.setImageBitmap(bitmap);

其中convertToJpeg()功能是:

    public static byte[] convertToJpeg(byte[] buffer, int w, int h, int quality) {
        YuvImage yuv_image = new YuvImage(buffer, ImageFormat.NV21, w, h, null);

        Rect rect = new Rect(0, 0, w, h);
        ByteArrayOutputStream output_stream = new ByteArrayOutputStream();
        yuv_image.compressToJpeg(rect, quality, output_stream);

        Bitmap sourceBmp = BitmapFactory.decodeByteArray(output_stream.toByteArray(), 0, output_stream.size());
        Bitmap destBmp = Bitmap.createScaledBitmap(sourceBmp, (int) (w * 0.75), (int) (h * 0.75), true);

        ByteArrayOutputStream pictureStream = new ByteArrayOutputStream();
        destBmp.compress(CompressFormat.JPEG, quality, pictureStream);
        byte[] pictureByteArray = pictureStream.toByteArray();

        return pictureByteArray;
    }

后decodeByteArray()呼叫我bitmap.getConfig() == ARGB_8888.

然而,我在屏幕上看到的是一些混乱的图片,原始图片中出现了一些模糊的绿色形状.

它出什么问题了？

Answer 1

事实证明,解决方案很简单.而且无需转换为JPEG.

Bitmap bm = Bitmap.createBitmap(width, height, Bitmap.Config.ARGB_8888);
bm.copyPixelsFromBuffer(ByteBuffer.wrap(rawData));