如何将NSString转换为NSArray

Question

我有一个字符串

NSString* str = @"[90, 5, 6]";

我需要将它转换为数组

NSArray * numbers = [90, 5 , 6];

我做了很长的路:

+ (NSArray*) stringToArray:(NSString*)str
{
    NSString *sep = @"[,";
    NSCharacterSet *set = [NSCharacterSet characterSetWithCharactersInString:sep];
    NSArray *temp=[str componentsSeparatedByCharactersInSet:set];

    NSMutableArray* numbers = [[NSMutableArray alloc] init];
    for (NSString* s in temp) {
        NSNumber *n = [NSNumber numberWithInteger:[s integerValue]];
        [numbers addObject:n];
    }

    return numbers;
}

是否有任何简洁快捷的方式进行此类转换？

谢谢

Answer 1

首先从字符串中删除不需要的字符,如空格和大括号:

NSString* str = @"[90, 5, 6]";
NSCharacterSet* characterSet = [[NSCharacterSet
                                 characterSetWithCharactersInString:@"0123456789,"] invertedSet];
NSString* newString = [[str componentsSeparatedByCharactersInSet:characterSet]
                       componentsJoinedByString:@""];

你会得到一个像这样的字符串:90,5,6.然后简单地使用逗号分割并转换为NSNumber:

NSArray* arrayOfStrings = [newString componentsSeparatedByString:@","];
NSMutableArray* arrayOfNumbers = [NSMutableArray arrayWithCapacity:arrayOfStrings.count];
for (NSString* string in arrayOfStrings) {
    [arrayOfNumbers addObject:[NSDecimalNumber decimalNumberWithString:string]];
}

使用此响应中的NSString类别,可以简化为:

NSArray* arrayOfStrings = [newString componentsSeparatedByString:@","];
NSArray* arrayOfNumbers = [arrayOfStrings valueForKey: @"decimalNumberValue"];

Answer 2

NSString* str = @"[90, 5, 6]";
NSCharacterSet *characterSet = [NSCharacterSet characterSetWithCharactersInString:@"[] "];
NSArray *array = [[[str componentsSeparatedByCharactersInSet:characterSet]
                        componentsJoinedByString:@""]     
                        componentsSeparatedByString:@","];